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Archy [21]
3 years ago
5

What is the term for a solid that forms when two liquids are mixed together

Chemistry
2 answers:
Paladinen [302]3 years ago
3 0
Answer: a precipitate.

Justification:

When two liquids are mixed together, their constituents may react chemically, forming new products whose chemical properties are different from those of the original constituents of the mixtures. 

Then, some of the products formed may be insoluble in the mix. In this case is when the precipitate (solid that cannot stand in the solution) will get formed.

The formation of  a precipitate is a clear signal that a chemical reaction has taken place between some constituents (elements or compounds) of the mix.

One example of this situation is the combination of a solution of baking soda, NaHCO₃(aq), and a solution of calcium chloride, CaCl₂ (aq).

Those two solutions are clear, and when combined will form a solid (precipitate) which is calcium carbonate, CaCO₃ (s). The calcium carbonate precipitates because it is not soluble in the mix.










Fittoniya [83]3 years ago
3 0

a precipitate

i go to k12 so yeah

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Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 8.00 g of octane is m
DerKrebs [107]

Answer:

11.3 g of H₂O will be produced.

Explanation:

The combustion is:

2C₈H₁₈ +  25O₂→  16CO₂  +  18H₂O

First of all, we determine the moles of the reactants in order to find out the limiting reactant.

8 g / 114g/mol = 0.0701 moles of octane

37g / 32 g/mol = 1.15 moles of oxygen

The limiting reagent is the octane. Let's see it by this rule of three:

25 moles of oxygen react to 2 moles of octane so  

1.15 moles of oxygen will react to ( 1.15 . 2)/ 25 = 0.092 moles of octane.

We do not have enough octane, we need 0.092 moles and we have 0.0701 moles. Now we work with the stoichiometry of the reaction so we make this rule of three:

2 moles of octane produce 18 moles of water

Then 0.0701 moles of octane may produce (0.0701 . 18)/2= 0.631 moles of water.

We convert the moles to mass → 0.631 mol . 18 g/1mol = 11.3 g of H₂O will be produced.

4 0
2 years ago
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tatyana61 [14]

Pure metals possess few important physical and metallic properties, such as melting point, boiling point, density, specific gravity, high malleability, ductility, and heat and electrical conductivity. These properties can be modified and enhanced by alloying it with some other metal or nonmetal, according to the need.

Alloys are made to:

Enhance the hardness of a metal: An alloy is harder than its components. Pure metals are generally soft. The hardness of a metal can be enhanced by alloying it with another metal or nonmetal.

Lower the melting point: Pure metals have a high melting point. The melting point lowers when pure metals are alloyed with other metals or nonmetals. This makes the metals easily fusible. This property is utilized to make useful alloys called solders.

Enhance tensile strength: Alloy formation increases the tensile strength of the parent metal.

Enhance corrosion resistance: Alloys are more resistant to corrosion than pure metals. Metals in pure form are chemically reactive and can be easily corroded by the surrounding atmospheric gases and moisture. Alloying a metal increases the inertness of the metal, which, in turn, increases corrosion resistance.

Modify color: The color of pure metal can be modified by alloying it with other metals or nonmetals containing suitable color pigments.

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5 0
3 years ago
What is Molecule made off?<br><br>a) Electrons<br>b) Protons<br>c) Atoms<br>d) Nuclei​
Naya [18.7K]
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6 0
2 years ago
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Murrr4er [49]

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=I_%7B2%7D" id="TexFormula1" title="I_{2}" alt="I_{2}" align="absmiddle" class="latex-formula">
gogolik [260]

Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

Explanation:

An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.

A Reductant thus exactly the opposite.

Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:

I2 --> 2I-.

The oxidation number reduced from 0 to -1.

In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.

Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

7 0
3 years ago
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