CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
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Answer:
B. increase the distance between the objects
Explanation:
A) increase the mass of one of the objects
Answer:
This is the tendency for particles in suspension to settle out of fluid in which they are contained and come to rest against a barrier.
Explanation:
In sedimentation, the particles are in a fluid and under the influence of forces , for example, gravitational forces, they settle and then come to rest when faced with a barrier.
The settling process is the process in which the particles fall out of liquid and sedimentation is the end of the process.
