Ask question

Ask question

All categories

3 years ago

10

Is carbon dioxide formed during incomplete combustion of methane? ...?

2 answers:

dexar [7]3 years ago

8 0

Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still </span>produced<span>, but </span>carbon<span> monoxide and </span>carbon<span> are </span>produced<span> instead of </span>carbon dioxide<span>. The </span>carbon<span> is released as soot. </span>Carbon<span> monoxide is a poisonous gas, which is one reason why </span>complete combustion<span> is preferred to </span>incomplete combustion<span>.</span>

Paladinen [302]3 years ago

4 0

Yes....of course but comes along with CO...that is carbon monoxide.
carbon di oxide is formed by complete combustion of methane . carbon monoxide is formed by incomplete combustion. <span>
</span>

You might be interested in

A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base

tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ = 0.00375 mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

$HN_3 + OH- ---> N^-_{3} + H_2O$

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction = 0.025 + 0.0133 = 0.0383 L

Concentration of $HN_3$ = $\dfrac{0.001755}{0.0383}$ = 0.0458 M

Concentration of $N^{-}_3$ = $\dfrac{ 0.001995 }{0.0383}$ = 0.0521 M

GIven that :

Ka = $1.9 x 10^{-5}$

Thus; it's pKa = 4.72

$pH =4.72 + log(\dfrac{ \ 0.0521}{0.0458})$

$pH =4.72 + log(1.1376)$

$pH =4.72 + 0.05598$

$pH =4.77598$

pH ≅ 4.80

3 0

3 years ago

Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a h

makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: $SiO_{2}+3C\rightarrow SiC+2CO$

Molar mass of SiC = 40.11 g/mol

Molar mass of $SiO_{2}$ = 60.08 g/mol

So, 100.0 kg of $SiO_{2}$ = $\frac{100.0\times 10^{3}}{60.08}$ moles of $SiO_{2}$ = 1664 moles of $SiO_{2}$

According to balanced equation, 1 mol of $SiO_{2}$ produces 1 mol of SiC

Therefore, 1664 moles of $SiO_{2}$ produce 1664 moles of SiC

Mass of 1664 moles of SiC = $(1664\times 40.11)g$ = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)] $\times 100$ %

= $\frac{51.4kg}{66.74kg}\times 100$ %

= 77.0%

4 0

3 years ago

Find the mass of 5.60 mol NaOH

olga_2 [115]

The mass is 224 grams of NaOH

7 0

3 years ago

What group of substances does this substance belong to?

HACTEHA [7]

In comparison see it is very easy in goolge

4 0

3 years ago

In an experiment, you use a ruler to measure two plants. What can you do with the data you gather?

Pepsi [2]

C. is the best choice

5 0

3 years ago

Read 2 more answers