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solniwko [45]
3 years ago
10

Is carbon dioxide formed during incomplete combustion of methane? ...?

Chemistry
2 answers:
dexar [7]3 years ago
8 0
Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still </span>produced<span>, but </span>carbon<span> monoxide and </span>carbon<span> are </span>produced<span> instead of </span>carbon dioxide<span>. The </span>carbon<span> is released as soot. </span>Carbon<span> monoxide is a poisonous gas, which is one reason why </span>complete combustion<span> is preferred to </span>incomplete combustion<span>.</span>
Paladinen [302]3 years ago
4 0
Yes....of course but comes along with CO...that is carbon monoxide.
carbon di oxide is formed by complete combustion of methane . carbon monoxide is formed by incomplete combustion. <span>
</span>
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Select the supplements that are minerals.
Jet001 [13]
<h3> The supplements that are minerals are</h3>
  1. calcium
  2. sodium
  3. iron
  4. zinc

<u><em> Explanation</em></u>

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      calcium-  needed  for muscle,hearing bone and  for the support of synthesis and function of cells

     sodium-   is needed to control blood  pressure  and  also for proper  muscle and nerve  function

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3 0
3 years ago
1. If I have 45 L of He in a balloon at 25 degrees celsius and increase the temperature of the
Greeley [361]

Use Charles' Law: V1/T1 = V2/T2. We assume the pressure and mass of the helium is constant. The units for temperature must be in Kelvin to use this equation (x °C = x + 273.15 K).

We want to solve for the new volume after the temperature is increased from 25 °C (298.15 K) to 55 °C (328.15 K). Since the volume and temperature of a gas at a constant pressure are directly proportional to each other, we should expect the new volume of the balloon to be greater than the initial 45 L.

Rearranging Charles' Law to solve for V2, we get V2 = V1T2/T1.  

(45 L)(328.15 K)/(298.15 K) = 49.5 ≈ 50 L (if we're considering sig figs).

7 0
3 years ago
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
What is the mass in grams of 358 mL of ethylene glycol?
frez [133]
The density of ethylene glycol is: D = 1.11 g/mL
D = m / V
and V = 358 mL
m = D * V
m = 1.11 g/mL * 358 mL
m = 397.38 g
Answer:
Mass is 397.38 g. 
6 0
3 years ago
The substance which does the dissolving in a solution is
oksano4ka [1.4K]

Answer:

solvents dissolve in liquids

6 0
3 years ago
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