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solniwko [45]
4 years ago
10

Is carbon dioxide formed during incomplete combustion of methane? ...?

Chemistry
2 answers:
dexar [7]4 years ago
8 0
Incomplete combustion<span> occurs when the supply of air or oxygen is poor. Water is still </span>produced<span>, but </span>carbon<span> monoxide and </span>carbon<span> are </span>produced<span> instead of </span>carbon dioxide<span>. The </span>carbon<span> is released as soot. </span>Carbon<span> monoxide is a poisonous gas, which is one reason why </span>complete combustion<span> is preferred to </span>incomplete combustion<span>.</span>
Paladinen [302]4 years ago
4 0
Yes....of course but comes along with CO...that is carbon monoxide.
carbon di oxide is formed by complete combustion of methane . carbon monoxide is formed by incomplete combustion. <span>
</span>
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If you put a plant across the room from a window, how will this affect the growth of the plant?
grin007 [14]
The plant will grow towards the light source.
3 0
3 years ago
Consider the equation: S+302 →SO3 Is this equation balanced? Why or why not?
Talja [164]
No, because there’s 6 Oxygens going in and only 3 going out. To balance:
2S+3O2 -> 2SO3
5 0
4 years ago
50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?
d1i1m1o1n [39]

Answer:

2.35 M

Explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

50.0gNaNO3*\frac{1molNaNO3}{85.00gNaNO3} = 0.588molNaNO3

Then you have to convert mL to L.

250mL*\frac{1L}{1000mL} = 0.250L

Now divide the mol by the L.

\frac{0.588mol NaNO3}{0.250L} = 2.352 M

Round to the smallest number of significant figures = 2.35M

7 0
3 years ago
Determine the ground-state electron configuration for each of the following elements: A. chlorine ______________________________
ki77a [65]

In ground-state electron configuration, the<u> principal quantum number</u> (n), <u>the orbital</u> (s, p, d, or f), and the total number of <u>electrons</u> are used to represent electron configurations.

Case 1 Ground-state electron configuration of elements.

A) Chlorine: 1s²2s²2p^{6}3s²3p^{5}

B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹

C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²

D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²

Case 2 : Number of valence electron in atoms

A) Sn -Tin - Four valence electrons

B) La - Lanthanum - Three valence electrons

C) Mn - Manganese - Seven valence electrons

D) Zn- Zinc - Two valence electrons

Case 3 Ground-state electronic configuration of ions

A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵

B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²

C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶

D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶

Learn more about Quantum numbers here brainly.com/question/2292596

#SPJ4

8 0
2 years ago
24. What volume of a 0.0200M calcium hydroxide is required to neutralize 35.00 mL of 0.0500M nitric acid
Natalka [10]

Answer:

THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.

Explanation:

Using

Ca VA / Cb Vb = Na / Nb

Ca = 0.0500 M

Va = 35 mL

Cb = 0.0200 M

Vb = unknown

Na = 2

Nb = 1

Equation for the reaction:

Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O

So therefore, we make Vb the subject of the equation and solve for it

Vb = Ca Va Nb / Cb Na

Vb = 0.0500 * 35 * 1 / 0.0200 * 2

Vb = 1.75 / 0.04

Vb = 43.75 mL

The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL

6 0
4 years ago
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