This is called a life span.
Molar mass:
Ag = 107.86 g/mol
Cu = 63.54 g/mol
Mole ratio:
Cu(s)+2 AgNO₃(aq)→Cu(NO₃)₂(aq)+2 Ag(s)
63.54 g Cu ------------- 2 x 107.86 g Ag
1.50 g Cu -------------- ??
Mass Ag = 1.50 x 2 x 107.86 / 63.54
Mass Ag = 32358 / 63.54
= 509.25 g of Ag
hope this helps!
<u>Answer:</u> The expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
<u>Explanation:</u>
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The given chemical equation follows:

1 mole of calcium fluoride produces 1 mole of calcium ions and 2 moles of fluorine ions.
The expression of
for above equation follows:
![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
Hence, the expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
Answer:
A. 14/15
B. 17/14
C. 5/12
Explanation:
Convert all so that the denominators are the same.
A. 3/5 + 1/3 = 9/15 + 5/15 = 14/15
B. 5/7 + 1/2 = 10/14 + 7/14 = 17/14
C. 1/6 + 2/8 = 4/24 + 6/24 = 10/24 = 5/12