Answer:
E= 2.158× 10*5N/C
Explanation:
K= 8.99×10*9, q= 6×10*-6C, d= 0.5m
E= kq/d*2
E= (8.99×10*9× 6×10*-6)/0.5*2
E= 215760
E= 2.158 ×10*5N/C
Answer:
<h2><em>
34.46m</em></h2>
Explanation:
Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;
v is the final velocity of the bicyclist = 26m/s
u is the initial velocity of the bicyclist = 0m/s
a is the acceleration due to gravity = 9.81m/s
s is the distance covered during travel
Substitute the given parameters into the formula above to get the distance traveled
26² = 0² + 2(9.81)s
676 = 19.62s
Divide both sides by 19.62
676/19.62 = 19.62s/19.62
s = 34.46m
<em>The distance traveled by the bicyclist during the race is 34.46m</em>
Answer:
Explanation:
Given
average speed of train
Maximum acceleration=0.05g
Now centripetal acceleration is


r=7346.93 m
(b)Radius of curvature=900 m
therefore 



Answer:
1,323 days left
Explanation:
147 x 10 = 1,470
1470 - 147 = 1,323
Hopefully this helps you :)
pls mark brainlest ;)