The moment of inertia of a cylinder is 0.016 kg m^2 with radius 6.0 cm. If the cylinder has a linear speed is 7.7 m/s, what is t
1 answer:
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Answer:
Explanation:
Given
Mass of object (m)=6 kg
falling height(h)=10 m
mass of water()=600 gm
temperature of water =15
specific heat of water
Let T be the Final Temperature of water
Here Object Potential Energy is converted into Heat energy which will be absorbed by water
Potential Energy(P.E.)
Heat supplied
T-16=0.234
This is not an efficient way of heating water as there is onlyincrease in temperature.
Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
Answer:
New moment of inertia will be
Explanation:
It is given initially angular velocity
Moment of inertia
Angular momentum is equal to
Now angular velocity is decreases to
As we know that angular momentum is conserved
So
So new moment of inertia will be