Ask question

Ask question

All categories

3 years ago

13

How are Aurora produced?

1 answer:

Juli2301 [7.4K]3 years ago

3 0

Answer:

The third one.

Explanation:

Atmospheric molecules releasing photons (light) in response to collisions with Solar Wind particles because when auroras are produced what actually happens is that the ions of the solar wind collide with atoms of oxygen and nitrogen from the Earth's atmosphere. The energy released during these collisions causes a colorful glowing halo around the poles which is the aurora.

You might be interested in

Which of the following are correct statements about the way an atom is put

Ann [662]

Answer:

valenc e shell

Explanation:

4 0

3 years ago

A stream of plasma? Solar wind, coronal mass ejection

OlgaM077 [116]

Answer:

coronal mass ejection

Explanation:

Solar wind is something that has to do with magnetism,

CME is " is a significant release of plasma and accompanying magnetic field from the solar corona," that often follows solar flares.

https://en.wikipedia. org/wiki/Coronal_mass_ejection

8 0

3 years ago

A 1/10th scale model of an airplane is tested in a wind tunnel. The reynolds number of the model is the same as that of the full

trasher [3.6K]

Answer:

of the velocity of a full size plane in the air

7 0

4 years ago

The mass of a hypothetical planet is 1/100 that of Earth and its radius is 1/4 that of Earth. If a person weighs 600 N on Earth,

omeli [17]

To solve this problem we will apply the Newtonian concept of gravitational acceleration produced by a planet. This relationship is given by:

$g = \frac{GM}{r^2}$

Where,

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius

The values given are based on the constants of the earth, so they can be expressed as

$M_p = \frac{1}{100} M_e$

$r_p = \frac{1}{4} r_e$

The relationship of gravity would then be given:

$g_e = \frac{GM_e}{r_e^2}$

The relationship with the new planet, from the gravity of the earth would be given

$g_p = \frac{GM_p}{r_p^2}$

$g_p = \frac{G(1/100)M_e}{(1/4 r_e)^2}$

$g_p = \frac{GM_e 16}{100 r_e^2}$

$g_p = 0.16 \frac{GM_e}{r_e^2}$

$g_p = 0.16g_e$

The relationship with the weight of the earth would be given as:

$W_e = m*g_e = 600N$

$W_p = m*g_p = m(0.16g_p)$

$W_p = (m*g_p)(0.16)$

$W_p = 600*0.16$

$W_p = 96N$

Therefore the weigh on this planet would be 96N

3 0

3 years ago

Symbion pandora has a symbiotic relationship with the Norway lobster. True False

pashok25 [27]

<em>The answer you are looking for is: </em>
<em><u>True</u>
Hope that helps!! </em>
<em>Have a wonderful day!! </em>
<em>If you ever need anything feel free to ask me!!</em>

8 0

3 years ago