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Lina20 [59]
3 years ago
10

Consider a 5kg rock and a 4.5g piece of paper held at the same height above the ground. What is true about the gravitational fie

ld at their location and the gravitational force on both objects ?
Physics
1 answer:
Volgvan3 years ago
4 0

Answer:

The gravitational field at any point is independent of the objects placed at that point such as a stone or paper.

And, also the gravitational force acting on a body is determined by the intensity of the field at that point.

Explanation:

Given,

The gravitational force between two bodies separated by a distance r is given by the relation,

                              F =  GMm / r²

Where,

                    M - the mass of the Earth

                    m - the mass of the object

                     r - the distance between the center of masses

Let m₁ be the mass of rock. Then force acting on the rock is given by

                                    F = m₁a

The gravitational force between the stone and Earth is given by

                                    F = GMm₁ / r²

Equating these two forces

                                     m₁a = GMm₁ / r²

Canceling out the mass of the stone.

This shows that the force component acceleration is independent of the mass of the stone.

Hence, it implies that the gravitational field at any point is independent of the objects placed at that point such as a stone or paper.

And, also the gravitational force acting on a body is determined by the intensity of the field at that point.

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A trained eye in the dark for an extended period of time may pick up a light stimulus from a light source, at the lowest radiate
frez [133]

Answer:

    #_photons = 30 photons / s

Explanation:

Let's start by finding the energy of a photon of light, let's use the Planck relation

         E = h f

the speed of light is related to wavelength and frequency

         c = λ f

we substitute

         E = h c /λ

         E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹

         E₀ = 3.978 10⁻¹⁹ J

now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second

          #_photons = 1 photon   (E / Eo)

          #_photons = 1  1.2 10⁻¹⁷ /3.978 10⁻¹⁹

          #_photons = 3.0 10¹

          #_photons = 30 photons / s

3 0
3 years ago
Which planet has the most extreme temperature variations
vichka [17]

Answer:

I believe Mercury has the most extreme temperatures in the solar system, ranging from -280?F at night to 800 degrees F during the day for parts of the surface.

Hope that helps! :)

5 0
3 years ago
Read 2 more answers
A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma
Dahasolnce [82]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{38}{57} =  \frac{2}{3}   \\  = 0.666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

4 0
3 years ago
A 0.540-kg bucket rests on a scale. Into this bucket you pour sand at the constant rate of 56.0 g/s. If the sand lands in the bu
romanna [79]

Answer:

a) 12.8212 N

b) 12.642 N

Explanation:

Mass of bucket = m = 0.54 kg

Rate of filling with sand  = 56.0 g/ sec = 0.056 kg/s

Speed of sand = 3.2 m/s

g= 9.8 m/sec2

<u>Condition (a);</u>

Mass of sand = Ms = 0.75 kg

So total mass becomes = bucket mass + sand mass = 0.54 +0.75=1.29 kg

== > total weight = 1.29 × 9.8 = 12.642 N

Now impact of sand = rate of filling × velocity = 0.056 × 3.2 =  0.1792 kg. m /sec2=0.1792 N

Scale reading is sum of impact of sand and weight force ;

i-e

scale reading = 12.642 N+0.1792 N = 12.8212 N

<u>Codition (b);</u>

bucket mass + sand mass = 0.54 +0.75=1.29 kg

==>weight = mg = 1.29 × 9.8 = 12.642 N (readily calculated above as well)

6 0
3 years ago
How many oxygen atoms are in the following compound?<br> 8 C120
Novosadov [1.4K]

Answer:

There are 12 oxygen atoms in 8C12O.

6 0
3 years ago
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