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Lina20 [59]
4 years ago
10

Relate the buoyant force to increased depth

Physics
1 answer:
swat324 years ago
5 0

Answer:The buoyant force doesn't depend on the overall depth of the object submerged. In other words, as long as the object is fully submerged, bringing it to a deeper and deeper depth will not change the buoyant force. This might seem strange since the pressure gets larger as you descend to deeper depths.:

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Why are objects that fall near earth’s surface rarely in free fall?
Sloan [31]

Answer:

Because of the presence of air resistance

Explanation:

When an object is in free fall, ideally there is only one force acting on it:

- The force of gravity, W = mg, that pushes the object downward (m= mass of the object, g = acceleration of gravity)

However, this is true only in absence of air (so, in a vacuum). When air is present, it exerts a frictional force on the object (called air resistance) with upward direction (opposite to the motion of free fall) and whose magnitude is proportional to the speed of the object.

Therefore, it turns out that as the object falls, its speed increases, and therefore the air resistance acting against it increases too; as a result, the at some point the air resistance becomes equal (in magnitude) to the force of gravity: when this happens, the net acceleration of the object becomes zero, and so the speed of the object does not increase anymore. This speed reached by the object is called terminal velocity.

3 0
3 years ago
The bass tones rattling the windows of the car next to you at a red light are at a __________.
Andrew [12]
... low frequency and high amplitude.
4 0
3 years ago
A 1500kg car is travelling at v=30m/s. The cars kinetic energy is? *
Anuta_ua [19.1K]

Hi there!

\large\boxed{\text{D. 675000J}}

Use the following formula to solve:

KE = 1/2mv², where:

KE = kinetic energy

m = mass (kg)

v = velocity (m/s)

Therefore:

KE = 1/2(1500)(30)²

KE = 1/2(1500)(900)

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4 0
3 years ago
PLZ HURRY!!!
MAVERICK [17]

Answer:

7.8 miles just did it

Explanation:

4 0
3 years ago
The pressure at the bottom of a cylindrical container with a cross-sectional area of 45.5 cm2 and holding a fluid of density 420
iris [78.8K]

Answer:

3.33 m

Explanation:

Pressure is the distributed force applied to the surface of an object per unit area. The force is applied perpendicular to the surface of the object. The SI unit of pressure is N/m² or Pa.

Hydrostatic pressure is the pressure that a fluid exerts at a point due to the force of gravity.

The relationship between  pressure on the bottom of the container,  atmospheric pressure and the pressure due to the depth of the fluid is given by:

P_{bottom}-P_{atm}=P_{depth}\\\\where\ P_{bottom}=pressure\ at\ the \ fluid\ bottom,\ P_{atm}=atmospheric\ pressure\\P_{depth}=pressure\ due\ to\ fluid\ depth=\rho gh. \ Hence:\\\\P_{bottom}-P_{atm}=\rho gh\\\\Given \ that\ P_{bottom}=115\ kPa=115*10^3\ Pa, let\ us\ assume\ P_{atm}=101\ kPa=101*10^3\ Pa,\rho=420\ kg/m^3,g=acceleration\ due\ to \ gravity=10\ m/s^2.\\\\Therefore:\\\\115*10^3-101*10^3=420*10*h\\\\14*10^3=4200h\\\\h=3.33\ m\\\\

6 0
3 years ago
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