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4 years ago

Relate the buoyant force to increased depth

1 answer:

swat324 years ago

5 0

Answer:The buoyant force doesn't depend on the overall depth of the object submerged. In other words, as long as the object is fully submerged, bringing it to a deeper and deeper depth will not change the buoyant force. This might seem strange since the pressure gets larger as you descend to deeper depths.:

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PLS HELP. WILL GIVE BRAINLIEST. PLS THIS IS WORTH 35 POINTS ON MY TEST

Nata [24]

Answer:

18m/s^2

Explanation:

Vf = Vi + at

t = distance/ average velocity

(120 + 0)/2 = 60 (average velocity)

400m/60m/s = 20/3 s

insert into first equation:

120 = 0 + a(20/3)

360 = 20a

18 = a

HOPE THIS HELPS!!!

5 0

2 years ago

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You are driving your car on a very cold late Fall day. You clear a turn and see a couple of pedestrians standing at the cross wa

Diano4ka-milaya [45]

Answer:

t_pass = 2.34 m

t_stop = 4.68 s

Thus, for the car passing at constant speed the pedestrian will have to wait less.

Explanation:

If the car is moving with constant speed, then the time taken by it will be given as:

$t_{pass} = \frac{D}{v}$

where,

t_pass = time taken = ?

D = Distance covered = 23 m

v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s

Therefore,

$t_{pass} = \frac{23\ m}{9.84\ m/s} \\$

t_pass = 2.34 m

Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:

$2as = v_{f}^{2} - v_{i}^2\\a = \frac{v_{f}^{2} - v_{i}^2}{2D}\\\\a = \frac{(0\ m/s)^{2}-(9.84\ m/s)^2}{(2)(23\ m)}\\\\a = -2.1\ m/s^2$

Now, for the passing time we use first equation of motion:

$v_{f} = v_{i} + at_{stop}\\t_{stop} = \frac{v_{f}-v_{i}}{a}\\\\t_{stop} = \frac{0\ m/s - 9.84\ m/s}{-2.1\ m/s^2}$

t_stop = 4.68 s

7 0

3 years ago

The resistance to an object being pulled over a surface is called _____.

andreyandreev [35.5K]

The resistance is a force called friction.

7 0

3 years ago

the sun on average is 93 billion miles from earth.how many meters is this? express it using power of ten and using a metric pref

Aleksandr [31]

Answer:

1.4966862 x 10^14 meters

1.55 x 10^11 km

3 0

3 years ago

What happens when light waves pass between two materials of different densities?

shusha [124]

Answer:

Light waves change speed when they pass across the boundary between two substances with a different density , such as air and glass. This causes them to change direction, an effect called refraction . the light speeds up going into a less dense substance, and the ray bends away from the normal.

4 0

3 years ago

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