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Arada [10]
4 years ago
11

A rolling ball will eventually stop rolling. Which describes one reason why this happens? The ball eventually loses its energy.

Friction converts some of the energy into heat energy. Friction converts some of the energy into kinetic energy.
Physics
1 answer:
eduard4 years ago
5 0
The ball will eventually loses its energy.
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Neil has 3 partially full cans of white pants. they contain 1/3 gallon, 1/5 gallon,and 1/2 gallon of paint About how much paint
Oliga [24]
He has 1 1/30 gallons, or 31/30 gallons, you can find this by setting all the fractions to a common denominator and adding them
7 0
4 years ago
The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength
Archy [21]

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

Learn more here:brainly.com/question/21431500

4 0
3 years ago
A converging lens is also known as a<br><br> •convex<br> •concave<br> •double<br> •refracted
Leni [432]

Answer:

Convex lens

Explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
Suppose we could shrink the Earth without changing its mass. At what fraction of its current radius would the free-fall accelera
spin [16.1K]

Answer:

R' = \frac{1}{\sqrt{3}}R

Explanation:

The acceleration due to gravity on the surface of the Earth is given by:

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the mass of the Earth

R is the radius of the Earth

Here we want to find the new Earth radius R' for which the gravitational acceleration at the surface, g', would be 3 times the current value of g:

g' = 3g

So we would have

\frac{GM}{R'^2}=3(\frac{GM}{R^2})

Solving the equation for R', we find

R'^2 = \frac{1}{3}R^2\\R' = \frac{1}{\sqrt{3}}R

7 0
3 years ago
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A system does 506 kj of work, and loses 266 kj of heat to the surroundings. what is the change in internal energy of the system?
babunello [35]

Answer:

The change in internal energy of the system = -772kJ

Explanation:

Given :

Heat lost by the system , a = -266KJ

Workdone by the system, W = -506KJ

The first law of thermodynamics states that:

Change in internal energy = q + w

Substituting values into the equation

Change in internal energy = (-266KJ) + (-506KJ)

Change in internal energy = -722KJ

7 0
3 years ago
Read 2 more answers
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