C9H20 + 14O2 --> 9CO2 + 10H2O
Answer:
Their isn't your examples but I will give you mine
Freezing, Evaporation and so on.
137 K
The volume is constant, so you can use <em>Gay-Lussac’s Pressure-Temperature Law </em>to calculate the new temperature (you don’t have to use the number of moles).
P1/T1 = P2/T2
Solve for T2: T2= T1 x P2/P1
P1 = 1.83 atm; T1 = 122 K
P2 = 2.05 atm; T2 = ?
∴ T2 = 122 K x (2.05 atm)/(1.83 atm) = 137 K
This result makes sense. Temperature is directly proportional to pressure. You increased the pressure by about 10 %, so the temperature increased by about 10 %.
