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Rom4ik [11]
3 years ago
6

What type of plant is thought to be the first plant?

Chemistry
2 answers:
Sergio [31]3 years ago
6 0
Angiosperms can produce flowers and fruits to aid in seed dispersal.
vladimir1956 [14]3 years ago
5 0

Answer:

Mosses

Explanation:

mosses are non-vascular plants, like  liverworts, that didn’t have deep roots and was the first plant plunged to earth.  

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Which of the following chemical equations is balanced?
muminat

Answer:

A, 4Fe 3O2 → 2Fe2O3

5 0
3 years ago
In a heating curve, when is the temperature constant? need answers!
Varvara68 [4.7K]
During a phase change
3 0
3 years ago
Read 2 more answers
A gas occupies a volume of 4.50 L at 44 kPa. What would be the new volume at 50 kPa?
oksano4ka [1.4K]

Explanation:

P1= 44 kpa

P2= 50 kpa

V1= 4.50 L

V2= ?

P1 V1= P2 V2

44 × 4.50 = 50 × V2

198= 50 × V2

V2 = 198/ 50

V2= 3.96 L "the new volume"

5 0
4 years ago
Which of the following pairs consists of a weak acid and a strong base? (1 point)
notka56 [123]

Answer:

acetic acid, sodium hydroxide

Explanation:

A strong acid is an acid that ionizes in water to give all its hydrogen ion. Weak acid only ionize to a certain degree. Acetic acid (CH3COOH) only ionize to give one hydrogen ion despite having other hydrogen atom. This account for its weak nature as an acid as shown below:

CH3COOH <=> H^+ + CH3COO^-

A strong base is a base that ionizes in water to give all it hydroxide ion. Sodium hydroxide(NaOH) ionizes to give all its hydroxide ions. This make it a strong base as shown below;

NaOH <=> Na^+ + OH^-

8 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
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