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Ber [7]
2 years ago
6

Write insoluble or soluble solution for the following mixtores12345​

Chemistry
1 answer:
dimaraw [331]2 years ago
6 0

<em>Gasoline</em><em> </em><em>in</em><em> </em><em>water</em><em> </em><em>=</em><em> </em><em>insoluble</em><em> </em>

<em>acetone</em><em> </em><em>in</em><em> </em><em>nail</em><em> </em><em>polished</em><em> </em><em>=</em><em> </em><em>soluble</em><em> </em>

<em>salt</em><em> </em><em>in</em><em> </em><em>alcohol</em><em> </em><em>=</em><em> </em><em>soluble</em><em> </em>

<em>oil</em><em> </em><em>in</em><em> </em><em>vinegar</em><em> </em><em>=</em><em> </em><em>insoluble</em><em> </em>

<em>tawas</em><em> </em><em>in</em><em> </em><em>water</em><em> </em><em>=</em><em> </em><em>soluble</em><em>.</em><em>.</em><em>.</em>

<em>Sorry</em><em> </em><em>if</em><em> </em><em>i</em><em> </em><em>am</em><em> </em><em>incorrect</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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             Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

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       1.8 \times 10^{-5} = k[0.105]x [0.15]y ............. (1)

       7.2 \times 10^{-5} = k [0.105]x [0.30]y ........... (2)

       3.6 \times 10^{-5} = k [0.0525]x [0.30]y ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3)  we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

     Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y

          Rate = k [HgCl2]1 [C_{2}O^{-2}_{4}]2

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               1.8 \times 10^{-5} = k[0.105]x [0.15]y  

            1.8 \times 10^{-5} = k [0.105]1 [0.15]2  

                      k = 7.6 \times 10^{-3} M^{-2} min^{-1}  

Thus, we can conclude that rate constant for the given reaction is 7.6 \times 10^{-3} M^{-2} min^{-1}.

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