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Maslowich
3 years ago
8

Which of the following is an example of a chemical change?

Chemistry
2 answers:
Lynna [10]3 years ago
6 0
The answer is burning paper

svetoff [14.1K]3 years ago
4 0
Burning paper...chemical changes are permanent and can't return to original form.<span />
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9.
Sholpan [36]

Answer: Your mass would be the same, but you would weigh less because the gravity on the moon is less than it is on Earth.

Explanation:

7 0
3 years ago
3 points
vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

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<em><u>I </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this </u></em><em><u>is </u></em><em><u>helpful</u></em>

8 0
3 years ago
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Sergio039 [100]

Answer:

second

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Explanation:

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3 0
3 years ago
What is the difference between random decay and theoretical?
denis-greek [22]

Answer:

Spontaneous and random. Decay is called spontaneous because the occur on their own and are unaffected by external factors like temperature, pressure, and many more. Decay is called random because we cannot determine the rate at which it decays but can only determine the probability of the decay.Oct 21, 2015

Explanation:

7 0
3 years ago
Consider the following reaction, equilibrium concentrations, and equilibrium constant at
REY [17]

Answer:

Equilibrium concentration of H_{2}O is 12.5 M

Explanation:

Given reaction: C_{2}H_{4}+H_{2}O\rightleftharpoons C_{2}H_{5}OH

Here, K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}

where K_{c} represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations

Here, [C_{2}H_{4}]=0.015M , [C_{2}H_{5}OH]=1.69M and K_{c}=9.0

So, [H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M

Hence equilibrium concentration of H_{2}O is 12.5 M

5 0
3 years ago
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