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Anarel [89]
3 years ago
11

Which of these four elements is the most reactive metal?​

Chemistry
2 answers:
rodikova [14]3 years ago
8 0

Answer:

Na

Explanation:

xenn [34]3 years ago
5 0

Answer:

It is Rb!!

for plato users

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6. Explain why there is no base unit for the dimension of volume.
weqwewe [10]
Because in SI, the expectation is that area and volume will be expressed in terms of a linear dimension( the metre) or its multiples.
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3 years ago
Methanol can be synthesized by combining carbon monoxide and hydrogen. CO(g) 2H2(g) CH3OH(g) . A reaction vessel contains the th
mihalych1998 [28]

Answer:

The answer is C. The partial pressure of hydrogen will be unchanged.

Explanation:

CO_{(g)} + 2H_{2(g)}  ⇒  CH_{3}OH

Argon with electronic configuration 1s^{2}  2s^{2}  2p^{6}  3s^{2}  3p^{6} (that is atomic number 18) is an inert gas making it unreactive and it's addition to the reaction has no effect on the partial pressure of either the reactant or production or the state of the system.

The partial pressure of hydrogen will remain unchanged on the addition of Argon.

6 0
4 years ago
H2SO4 + 2NaNO2 → 2HNO2 + Na2SO4
dem82 [27]
<h3>Answer:</h3>

23.459 g NaNO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] H₂SO₄ + 2NaNO₂ → 2HNO₂ + Na₂SO₄

[Given] 24.14714 g Na₂SO₄

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol Na₂SO₄ = 2 mol NaNO₂

Molar Mass of Na - 22.99 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of Na₂SO₄ - 2(22.99) + 32.07 + 4(16.00) = 142.05 g/mol

Molar Mass of NaNO₂ - 22.99 + 14.01 + 2(16.00) = 69.00 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 24.14714 \ g \ Na_2SO_4(\frac{1 \ mol \ Na_2SO_4}{142.05 \ g \ Na_2SO_4})(\frac{2 \ mol \ NaNO_2}{1 \ mol \ Na_2SO_4})(\frac{69.00 \ g \ NaNO_2}{1 \ mol \ NaNO_2})
  2. Multiply/Divide:                                                                                                \displaystyle 23.4587 \ g \ NaNO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>

23.4587 g NaNO₂ ≈ 23.459 g NaNO₂

8 0
3 years ago
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Calculation of Original pH from Final pH after Titration A biochemist has 100 mL of a 0.10 M solution of a weak acid with a pKa
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4 years ago
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What kind of bond is N and C
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