1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mihalych1998 [28]
2 years ago
14

Not in book

Physics
1 answer:
umka2103 [35]2 years ago
6 0

Answer:

x=2.4365\ m

and

x=-1.4365\ m

Explanation:

Given:

  • first charge, q_1=5\times 10^{-3}\ C
  • second charge, q_2=3\times 10^{-3}\ C
  • position of first charge, x_1=-2\ m
  • position of second charge, x_2=-1\ m

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

E_1=E_2

  • since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}

\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}

3(r^2+1+2r)=5r^2

2r^2-6r-3=0

r=3.4365 \&\ r=-0.4365

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

x=-1+3.4365=2.4365\ m

and

x=-1-0.4365=-1.4365\ m

You might be interested in
Are S waves transvers? (Need answer fast, hurry)
pychu [463]

Answer:

Yes they are transverse

Explanation:

7 0
3 years ago
Read 2 more answers
Failure to accomplish Erikson’s psychosocial task of late adulthood leads to despair.
Y_Kistochka [10]
False is the answer
6 0
3 years ago
Read 2 more answers
Which of the following decreases with increasing atomic number in Group 2A?
Semenov [28]
"Ionization energy" is the one among the following choices given in the question that <span>decreases with increasing atomic number in Group 2A. The correct option among all the options that are given in the question is the third option or option "C". I hope that the answer has helped you.</span>
7 0
2 years ago
Read 2 more answers
How much gravitational potential energy does a 45.2 kg object have when it is 21.9m above the ground?
Blizzard [7]

Answer:

Explanation:

The formula for gravitational potential energy is

Ep = m · g · h   Assuming that the acceleration is g = 10m/s²

Ep = 45.4 · 10 · 21.9 = 9,942.6 J

God is with you!!!

6 0
3 years ago
What is scientific inquiry (method) ?
Shtirlitz [24]
A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses
6 0
3 years ago
Other questions:
  • What is an astronomer? Answer in the simpliest way please.
    10·1 answer
  • Which is more work, pushing with 115 N over 15m or lifting 20N over 10 m?
    14·2 answers
  • The total magnification of a specimen being viewed with a 10X ocular lens and a 40X objective lens is _____.
    10·1 answer
  • A square coil of wire with side 8.0 cm and 50 turns sits in a uniform magnetic field that is perpendicular to the plane of the c
    15·1 answer
  • an object that is 8 cm tall is located 2.5 m in front of a plane mirror. The image formed by the mirror appears to be. Find di a
    15·1 answer
  • As the motor speeds up, the value of current decreases because of A. Friction loss B. Increase in resistance C. Increase in back
    12·1 answer
  • Which of the following<br>is not the unit of distance​
    13·2 answers
  • Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if
    15·1 answer
  • What is the role of friction when ; a boats engine stops
    6·1 answer
  • Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!