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Lynna [10]
3 years ago
6

Calculate the missing variable....

Physics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

option b

Explanation:

from the given formula, s=d/t

make t the subject of the formula we have

t=d/s

5/100

0.5

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A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does
Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right) (1)

Where:

y(t) - Position of the mass as a function of time, measured in meters.

A - Amplitude, measured in meters.

k - Spring constant, measured in newtons per meter.

m - Mass of the block, measured in kilograms.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

k = \frac{m\cdot g}{\Delta y} (2)

Where:

g - Gravitational acceleration, measured in meters per square second.

\Delta y - Deformation of the spring due to gravity, measured in meters.

If we know that m=1.65\,kg, g = 9.807\,\frac{m}{s^{2}} and \Delta y = 0.260\,m, then the spring constant is:

k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}

k = 62.237\,\frac{N}{m}

If we know that A = 0.130\,m, k = 62.237\,\frac{N}{m}, m=1.65\,kg, x(t) = 0\,m and \phi = 0\,rad, then (1) is reduced into this form:

0.130\cdot \cos (6.142\cdot t)=0 (1)

And now we solve for t. Given that cosine is a periodic function, we are only interested in the least value of t such that mass reaches equilibrium position. Then:

\cos (6.142\cdot t) = 0

6.142\cdot t = \cos^{-1} 0

t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s

t \approx 0.255\,s

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

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Ksju [112]
Light travels at a speed of:
c=3 \cdot 10^8 m/s
The distance between Mercury and Sun is S=6.02 \cdot 10^7 km=6.02 \cdot 10^{10} m, so the time it takes is
t= \frac{S}{c}= \frac{6.02 \cdot 10^{10} m}{3 \cdot 10^8 m/s}  =200.7 s
if we want to convert this into minutes, keeping in mind that 1 min = 60 seconds, we should divide this value by 60:
t= \frac{200.7 s}{60 s/min}=3.34 min
6 0
4 years ago
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Answer:

revolution

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