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Ede4ka [16]
3 years ago
8

Two long wires hang vertically. wire 1 carries an upward current of 1.60

Physics
1 answer:
charle [14.2K]3 years ago
7 0
3.00 is my correct answer this is what my teacher told me.thanks
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A bulb converts 9J of energy in each second from an input of 100J of energy. Calculate efficiency of this light bulb
77julia77 [94]
Efficiency is calculated through dividing the actual mechanical advantage by the hypothetical mechanical advantage:

- the actual mechanical advantage is 9J because that's how much work the light bulb doing

- the hypo. mechanical advantage is 100J. Ideally, in a perfect world, the light bulb can convert 100J input into 100J output, but do to resistance and other factors it is not possible.

\frac{9}{100}  = .09
change the decimal to a percentage:

.09 = 9\%
the light bulb had 9% efficiency
8 0
4 years ago
If the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force
just olya [345]
The object would stay constant
5 0
3 years ago
What causes the bright lines seen in the emission spectrum?
Snezhnost [94]
Base in your questions that ask what cause the bright lines seen in the emission spectrum and i think the best answer to that is the H2 gas is used when protons was heated so the electron absorb all the photons and get exited and resulted by given of a light.
7 0
3 years ago
ATTENTION! I NEED THIS DONE ASAP NO LINKS !!!<br> THIS IS A SCIENCE QUESTION
nata0808 [166]

Answer:

Science seeks to broaden our knowledge base, while engineering designs solutions and problems.

Explanation:

4 0
3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
kramer

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

3 0
3 years ago
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