Molecular chemical equation:
K₂C₂O₄(aq)+Pb(OH)₂(aq) → 2KOH(aq) + PbC₂O₄<span>(s).
Ionic equation:
2K</span>⁺(aq) + C₂O₄²⁻(aq) + Pb²⁺(aq) + 2OH⁻(aq) → 2K⁺(aq) +2OH⁻(aq)+PbC₂O₄(s)
Net ionic eqation:
C₂O₄²⁻(aq) + Pb²⁺(aq) → PbC₂O₄(s).
s is solid, do not dissolve in water, potassiom hydroxide is trong base and dissolves in water.
Hi!
The correct option would be A.
This is because the displacement reaction would take place as follows
Ca + ZnCl2 --> CaCl2 + Zn
A displacement reaction is one in which a substitution occurs, as the more reactive element in the mixture replaces one that is less reactive.
In the electrochemical series, we find Ca higher than Zn, which is indicative of Ca being more reactive, and having the capacity to displace Zn to form a compound.
Option D would be incorrect as no such substitution occurs.
Option B would be incorrect because again, there is no substitution occurring, and also because two metals alone (Ca and Zn in our case) can never react to form a compound.
Option C would be incorrect because it is not possible because CaCl and ZnCl are forms that are too unstable to exist due to an overall positive charge.
Hope this helps!
The correct answer is option 3. A real gas behaves least like an ideal gas under the conditions of high temperature and low pressure. At this temperature and pressure, the molecules are close to each other and collisions or interactions are very likely to happen which is not an ideal gas.
It will have an overall positive charge.
Answer:
pKa of the acid HA with given equilibrium concentrations is 6.8
Explanation:
The dissolution reaction is:
HA ⇔ H⁺ + A⁻
So at equilibrium, Ka is calculated as below
Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260
= 15.38 x 10⁻⁸
Hence, by definition,
pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813
