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2 years ago

PLEASE answer! Brainly if more than 2 answers - Liked comment - 5-star rating

Chemistry

1 answer:

Bad White [126]2 years ago

5 0

A) hydrogen

B)Two hydrogen atoms fuse together which forms a helium atom.

Hope this helps!

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What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?

garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

$M=\frac{4.4mol}{1.5L} =2.9 M$

7 0

2 years ago

Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.

frez [133]

Answer:

294.87 gm CaCl_2

Explanation:

The computation of the mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm CaCl_2

7 0

3 years ago

What is the molecular formula for C5H7 if its molar mass is 536 g/mol?

hodyreva [135]

Answer:

(C5H7)8

Explanation:

It's empirical formula is given as; C5H7

Molar mass of carbon(C) = 12 g/mol

Molar mass of hydrogen(H) = 1 g/mol

We are told that it's molar mass is 536 g/mol.

To find the molecular formula;

Molecular formula = n × empirical formula

Thus;

n = 536/((12 × 5) + (1 × 7))

n = 8

Thus;

Molecular formula = (C5H7)8

8 0

3 years ago

Please help i need this like in the next 5 minutes

lana66690 [7]

it is the second one

7 0

3 years ago

Read 2 more answers

A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$