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OverLord2011 [107]
3 years ago
13

I dont know the steps to percent yield homework

Chemistry
1 answer:
wariber [46]3 years ago
5 0
What are you specifically asking <span />
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What is the difference between docosahexaenoate (DHA) and 19,20-dihydroxydocosapentaenoate (19,20-DHDP)? Only DHA is a polyunsat
andrew11 [14]

Answer:

Explanation:

The correct answer is 19, 20 DHDP is more polar than DHA. This is as a result of the presence of two hydroxyl groups.

4 0
3 years ago
Quiz. Formula Weight and % Composition
astraxan [27]

Answer:

#1- the percentage is 2.77%

#2 - 218.1336g

#3- 7.89%

#4- 63.8489g

#5- 136.1406g

#6- 340.3515g

#7- 2.387238

#8-  

Explanation:

7 0
3 years ago
Which statements are true? Check all that apply. Check all that apply. The higher the temperature, the more soluble most ionic s
snow_lady [41]

Answer:

The higher the temperature, the more soluble most ionic solids are in water

As you cool a saturated solution from high temperature to low temperature, solids start to crystallize out of solution if you achieve a supersaturated solution.

If you raise the temperature of a saturated solution, you can (usually) add more solute and make the solution even more concentrated.

Explanation:

For many ionic solids, solubility in water increases with increase in the temperature of the solution.

This implies that increasing the temperature allow more solute to dissolve in the solvent, supersaturation may be achieved by so doing. As the solution is cooled, the solid crystalizes out of solution hence the answers above.

8 0
3 years ago
What can Be done to reduce the negative impact of pollution
Snowcat [4.5K]
Get a majority of the world to go green
3 0
3 years ago
BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.
Yakvenalex [24]

Answer:

T_2=-125.58\°C

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Whereas solving for the final temperature T2, we get:

T_2=\frac{T_1P_2}{P_1}

Thus, we plug in the given data (temperature in Kelvins) to obtain:

T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C

Best regards!

3 0
3 years ago
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