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pantera1 [17]
3 years ago
10

What is the mass, in grams, of 9.01 x 1024 molecules of methanol (CH, OH) ?

Chemistry
1 answer:
Zina [86]3 years ago
3 0

Answer:

480.6 g

Explanation:

Given data:

Number of molecules of methanol = 9.01 ×10²⁴

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

9.01 ×10²⁴molecules ×1 mol /6.022 × 10²³ molecules

1.5 ×10¹ mol

15 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 15 mol × 32.04 g/mol

Mass = 480.6 g

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Paleontologists have uncovered new fossils from Tiktaalik roseae, which, while still a fish, is considered a transitional fossil that also has traits common to the first four-footed animals. This more complete picture of Tiktaalik suggests that the creature had strong, mobile hind fins.

Explanation:

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What is the only chemical that is liquid at room temperature
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The only chemical that is a liquid at room temperature is Mercury. It's toxic, and has a high vapor pressure at room temperature.
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Consider the equation below. Upper C a upper C upper O subscript 3 (s) double-headed arrow upper C a upper O (s) plus upper C up
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The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes su
masha68 [24]

Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

Temperature,

= 4.483 K (below)

Now,

The formula of temperature conversion will be:

⇒ T(^{\circ} C)=T(K)-273.15

By putting the values, we get

⇒            =4.483-273.15

⇒            =-268.667^{\circ} C

Thus the above is the correct answer.

3 0
3 years ago
9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A l
Arte-miy333 [17]

We have that the the liquid is

  • C_2H_5OH (ethanol
  • And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

  • A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
  • A low-boiling liquid was obtained instead of ethylene.
  • What was the liquid, and how might the reaction conditions be changed to give ethylene

<h3>Ethylene formation</h3>

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

  • C_2H_5OH (ethanol

For more information on Ethylene visit

brainly.com/question/20117360

8 0
2 years ago
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