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slavikrds [6]
4 years ago
12

Select the correct answer. Which two factors does the power of a machine depend on? A. work and distance B. force and distance C

. work and time D. time and distance
Physics
1 answer:
scoundrel [369]4 years ago
6 0
<h2>Hello!</h2>

The answer is: C. work and time

<h2>Why?</h2>

We need to remember the mechanical power formula. This formula states that power is the amount of work applied during a determined time interval.

Mechanical power is equal to the division of Work by the time while that work is applied.

Power=\frac{Work}{Time}

For example, if we want to calculate the power in Watt, the formula will be :

Power=\frac{Joule}{Second} =Watt

We have another unit of measurement such as Horsepower (Hp)

Hp=\frac{Lbf.ft}{min}

Have a nice day!

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A passenger walks from one side of a ferry to the other as it approaches a dock.Passenger's velocity is 1.55 m/s due north relat
victus00 [196]

Answer:\theta =33.22^{\circ}

Explanation:

Given

Velocity of Passenger w.r.t to Ferry

v_{pf}=v_p-v_f=1.55\hat{j}-------1

Velocity of Passenger w.r.t to water

v_{pw}=v_p-v_w=4.5\left ( -\hat{i}+\hat{j}\right )--------2

Subtract 2 from 1

v_f-v_w=-4.5\hat{i}+2.95\hat{j}

(b)direction

tan\theta =\frac{2.95}{4.5}=0.655

\theta =33.22^{\circ} North of west

5 0
4 years ago
A stone whirled on a string experiences a centripetal acceleration of 10 m/s². If the string were shortened to half its length (
LUCKY_DIMON [66]

Answer:

a = 80 m/s²

Explanation:

10 = v²/r

a = (2v)²/(r/2)

a = 4v²•(2/r)

a = 8(v²/r)

a = 8(10)

a = 80 m/s²

4 0
3 years ago
How high up is a 3 kg object that has 300 joules of energy?
Advocard [28]
Use the formula pe=mgh to answer the height <span />
7 0
3 years ago
What are some of the objects found in space and their characteristics?
RideAnS [48]

Answer:

meteor

Explanation:

big rock or metal maybe

6 0
3 years ago
A string under a tension of 36 N is used to whirl a rock in a horizontal circle of radius 3.6 m at a speed of 16.12 m/s. The str
ExtremeBDS [4]

Answer:

6010.457N

Explanation:

Centripetal acceleration = a= V²/R

At a radius of 3.6m and velocity of 16.12m/s,

Acceleration is

a = 16.12²/ 3.6 = 72.182 m/s²

Force = Mass (m) * Acceleration (a)

36 = m * 72.182

m = 36/72.182

At breaking point

Radius = 0.468 m and Velocity = 75.1 m/s

a = V²/R = 75.1²/0.468

a = 12051.3 m/s

F = Mass(m) * Acceleration (a)

F = m * 12051.3

m = F/ 12051.3

Settings the ratio of mass equal

m = m

=> 36/72.182 = F/12051.3

F = 12051.3 * 36/72.182

F = 6010.457N

3 0
3 years ago
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