20 hfzzigzgizugzgizgiziffuzufzufzufzifzifz
Answer:
cal
Explanation:
= mass of ice = 100 g = 0.1 kg
= specific heat of ice = 0.5 cal/(kg°C)
= specific heat of water = 1 cal/(kg°C)
= Latent heat of fusion of ice = 80 J/g
= initial temperature of ice = - 20 °C
= final temperature of ice = 50 °C
Q = Heat gained
Heat gained is given as
cal
speed at end is accn of gravity x time
9.81x12=just over98.1m/s
Answer:
E = 2,575 eV
Explanation:
For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength
E = h f
c = λ f
Where the Planck constant has a value of 6.63 10⁻³⁴ J s
Let's replace
E = h c / λ
Let's calculate for wavelengths
λ = 4.83 10-7 m (blue)
E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷
E = 4.12 10-19 J
The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J
E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
E = 2,575 eV
