Which is more stable hydroxyl isopropyl or benzhydrol radical?

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of $NH_{3}$ is as follows:.

$2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)$

And, initially only $NH_{3}$ is present.

The given data is as follows.

$P_{NH_{3}}$ = 2.3 atm at equilibrium

$P_{H_{2}} = 3 \times P_{N_{2}}$ = 0.69 atm

Therefore,

$P_{N_{2}} = \frac{0.69 atm}{3}$

= 0.23 aatm

So, $P_{NH_{3}}$ = 2.3 - 2(0.23)

= 1.84 atm

Now, expression for $K_{p}$ will be as follows.

$K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}$

$K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}$

= $\frac{0.23 \times 0.33}{3.39}$

= 0.0224

or, $K_{p} = 2.2 \times 10^{-2}$

Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is $2.2 \times 10^{-2}$ .

6 0

4 years ago

A. 207 kJ<br> B. 4730 kJ<br> C. 9460 kJ<br> D. 414 kJ

Leno4ka [110]

Answer:

$\boxed {\boxed {\sf C. \ 9460 \ kJ}}$

Explanation:

The formula we must use is given to us:

$q=mL_{vapor}$

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

We know the sample is copper.
Find that element on the table, then the third box tells us it's latent heat of vaporization is 4730 kJ/kg

Now we know:

$m= 2 \ kg \\L_{vapor}=4730 \ kJ/kg$

Substitute the values into the formula.

$q=(2 \ kg ) * (4730 \ kJ/kg)$

Multiply. Note that the kilograms (kg) will cancel each other out.

$q= 2* 4730 \ kJ$

$q= 9460 \ kJ$

<u>9460 kilojoules</u> are required to vaporize 2 kilograms of copper.

3 0

3 years ago

Imagine that a new polyatomic anion called "platoate" is invented. What would an acid of "platoate" be named?

o-na [289]

<h3>Answer:</h3>

Platoic Acid

<h3>Explanation:</h3>

While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.

Examples:

HCOOH → HCOO⁻ + H⁺

Formic acid Formate Ion

H₃CCOOH → H₃CCOO⁻ + H⁺

Acetic acid Acetate Ion

H₅C₂COOH → H₅C₂COO⁻ + H⁺

Propanoic acid Propanoate Ion

Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid <em>i.e.</em>

RCOO⁻ + H⁺ → RCOOH

Platoate Ion Platoic Acid

8 0

4 years ago

Read 2 more answers

Be sure to answer all parts. Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everythi

Kazeer [188]

Answer:

Half life = 79.67 sec

Explanation:

Given that:

k = $8.7\times 10^{-3}\ s^{-1}$

The expression for half life is shown below as:-

$t_{1/2}=\frac{\ln2}{k}$

Where, k is rate constant

So,

$t_{1/2}=\frac{\ln2}{8.7\times 10^{-3}\ s^{-1}}$

$t_{1/2}=114.94252\ln \left(2\right)\ sec=79.67\ sec$

Half life = 79.67 sec

6 0

3 years ago

For the reaction ag2s(s) ⇌ 2 ag+ (aq) + s2- (aq), keq = 2.4 × 10-4 and the equilibrium concentration of silver ion is [ag+] = 2.

Juliette [100K]

Answer : The concentration of silver ion is, $3.8\times 10^{-3}M$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq)+S^{2-}(aq)$