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3 years ago

Example of gases collected through upward delivery

Chemistry

2 answers:

taurus [48]3 years ago

8 0

Answer:

Gases which are collected by this process are Hydrogen, ammonia etc. In this process The more dense gases are collected in a gas jar. Carbon dioxide, Nitrogen dioxide are collected by this way. Air is displaced upward thus, this process is known as upward delivery...!

fgiga [73]3 years ago

4 0

Answer:

In this process The more dense gases are collected in a gas jar. Carbon dioxide, Nitrogen dioxide are collected by this way. Air is displaced upward thus, this process is known as upward delivery

Hope it helped :)

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What diffuses more quickly: tetracarbon decahydride (C4H10) or iodine (12)? By how much?

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Answer: Butane will effuse more quickly because it has a smaller molar mass

Explanation:

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Molar mass of I2 = 253.808 g/mole

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2 years ago

The pH of a solution prepared by mixing 40.00 mL of 0.10 M NH3 with 50.00 mL of 0.10 M NH4Cl and 30mL of 0.05 M H2SO4 is 5.17. A

liq [111]

Answer:

Following are the answer to this question:

Explanation:

The value of pH solution is =5.17 So, the p^{OH}:

$p^{OH}$ =14-56.17

=8.823

The volume of the $NH_{3}$ = 40.00 ml

convert into the liter= 0.040L

The value of the concentrated $NH_{3}$ =0.10 M

The volume of the $NH_{4}Cl$ = 50.00 ml

convert into the liter= 0.050L

The value of concentrated $NH_{4}Cl$ = 0.10 M

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convert into the liter= 0.030L

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Calculating total volume=(0.40+0.050+0.030)

=0.120 L

calculating the new concentrated value of $NH_3$ = $\frac{0.10\times 0.040}{0.120}= 0.33 \ M$

calculating the new concentrated value of $NH_4Cl$ = $\frac{0.050\times 0.10}{0.120}= 0.04166 \ M$ calculating the new concentrated value of $H_2So_4= \frac{0.030\times 0.05}{0.120}= 0.0125 \ M$ when 1 mol $H_2So_4$ produced 2 mols $H^{+}$ so, 0.0125 in $H_2So_4$ produced:

$=4 \times (2 \times 0.0125) \ mol H^{+}\\\\= 0.025 mol H^{+}$

create the ICE table:

$NH_3 \ \ \ \ \ \ \ \ + H^{+} \ \ \ \ \ \ \longrightarrow NH_4^{+}$

I (m) 0.033(m) 0.025 0.04166

C -0.025 -0.025 + 0.025

E 8.3\times 10^{-3} 0 0.0667

now calculating pH:

when ph= 8.83:

$P^{H}= p^{kb}|+ \log\frac{[NH_4^{+}]}{[NH_3]}\\\\8.83=p^{kb}+\log\frac{0.0667}{8.3 \times 10^{-3}}\\\\p^{kb}=8.83-0.9069\\\\ \ \ \ =7.7231 \\\\\ The P^{kb} \ for \ NH_3 \ is =7.7231\\\\\ The P^{kb} \ for N^{+}H_4=14-7.7231\\\\\ \ \ \ \ \ =6.2769$

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3 years ago

How many total atoms are in 3Na2SO4?

tigry1 [53]

Answer:

A. 21

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Reika [66]

Answer:

<em>The correct option is D) Cows release all of their energy as heat.</em>

Explanation:

Not all of the energy gets travelled from one trophic level to another. Observations have shown that only 10% of the energy travels from one trophic level to another when an organism of the upper trophic level consumes an organism of the lower trophic level. This is because most of the energy is lost by organisms as heat.

So, let's consider that there is 100% energy in plants that the cow eat. The cows will only receive 10% of the energy from the plants. The organisms that will eat the cows will only receive 1%of the energy.

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3 years ago

Example of gases collected through upward delivery​

Example of gases collected through upward delivery