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allochka39001 [22]
2 years ago
15

Law of Conservation of Mass in terms of atoms

Chemistry
1 answer:
VARVARA [1.3K]2 years ago
4 0

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

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The atomic bomb detonated in 1945 produced an explosion equivalent to 18,600 tons of TNT from 5 kg of _____.
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JAPAN GOT NUKED LOL its so funny
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3 years ago
What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?
worty [1.4K]
B. This is because the Hydrogen and Oxygen need balanced out.

Current-

C-1            |        C-1
H-4            |         H-2
O-2            |         O-3


Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

<span>CH4 + 2O2 → CO2 + 2H2O</span>
C-1            |        C-1
H-4            |         H-4
O-4            |        O-4


4 0
3 years ago
What is the charge of a proton? neutral negative positive
Brilliant_brown [7]
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4 0
3 years ago
Magnesium and oxygen balanced
11Alexandr11 [23.1K]
2Mg+ O₂= 2MgO
The charge of Mg is+2 and the charge of Oxygen is -2. 2 oxygen atoms will have a charge of -4 so the Mg atoms have to equal +4. A coefficient of 2 for the Mg atoms will balance it out 
8 0
2 years ago
A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C
Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}

Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}

Equivalent weight is calculated by dividing the molecular weight by n factor.   {\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}

n= charge for charged species  , For Ca^{2+} , n =2

{\text{Equivalent weight}}=\frac{40}{2}=20g

\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents

Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L

Thus there will be 0.00002 meq per Liter of the solution.

3 0
3 years ago
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