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allochka39001 [22]
3 years ago
15

Law of Conservation of Mass in terms of atoms

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

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Write the MOLECULAR EQUATION between iron and copper (II) sulfate.
Aleksandr-060686 [28]

Answer : The balanced molecular equation will be:

Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)

Explanation :

Molecular equation : It is a balanced chemical reaction in which the ionic compounds are expressed as the molecules instead of component ions.

According to the question, when iron react with copper (II) sulfate then it react to give iron (II) sulfate and copper as a product. In this reaction, iron is more reactive metal than the copper metal. So, it can easily displace copper metal form the solution.

The balanced molecular equation will be:

Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)

4 0
3 years ago
A sample of gas occupying 350 mL at 25 C is cooled to -25 C. What volume will it occupy if the pressure is held constant?
leonid [27]

Answer:

I hac no ideasghjjbhnn

7 0
3 years ago
At a certain concentration of H2 and NH3, the initial rate of reaction is 0.120 M / s. What would the initial rate of the reacti
mel-nik [20]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

rate=k[H_2]^2[NH_3]

At a certain concentration of H_2 and [tex]I_2, the initial rate of reaction is 0.120 M/s. What would the initial rate of the reaction be if the concentration of [tex]H_2 were halved.Answer : The initial rate of the reaction will be, 0.03 M/sExplanation :Rate law expression for the reaction:[tex]rate=k[H_2]^2[NH_3]

As we are given that:

Initial rate = 0.120 M/s

Expression for rate law for first observation:

0.120=k[H_2]^2[NH_3] ....(1)

Expression for rate law for second observation:

R=k(\frac{[H_2]}{2})^2[NH_3] ....(2)

Dividing 2 by 1, we get:

\frac{R}{0.120}=\frac{k(\frac{[H_2]}{2})^2[NH_3]}{k[H_2]^2[NH_3]}

\frac{R}{0.120}=\frac{1}{4}

R=0.03M/s

Therefore, the initial rate of the reaction will be, 0.03 M/s

5 0
3 years ago
In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t
Arada [10]

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^{-kt}

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}

       [A]=0.529M

7 0
4 years ago
Put the following metric units in order from largest to smallest pL, mL, dL, kL
earnstyle [38]

Answer:

kL, dL, mL, pL

Explanation:

pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.

mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.

dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.

kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.

8 0
3 years ago
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