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Zinaida [17]
4 years ago
12

Radar use reflected microwaves to detect objects and measure their... what?

Physics
1 answer:
Sloan [31]4 years ago
7 0
Height and depth..... for sure....

You might be interested in
Help me with this problem please? c:
deff fn [24]
30*3*60=5400
300*2=600
1500*3=4500
200*10*60=120000

the computer uses more energy. 
(you can multiply all results by 60 to get the energy in J, but it's not necessary for the comparison)
5 0
3 years ago
You illuminate a slit with a width of 77.7 μm with a light of wavelength 721 nm and observe the resulting diffraction pattern on
SVETLANKA909090 [29]

Answer:

The width is  Z = 0.0424 \ m

Explanation:

From the question we are told that

    The width of the slit is d  =  77.7 \mu m  =  77.7 *10^{-6} \ m

    The wavelength of the light is  \lambda  = 721  \ nm

      The position of the screen is  D = 2.83 \ m

Generally angle at which the first minimum  of the interference pattern the  light occurs  is mathematically  represented as

        \theta  =  sin ^{-1}[\frac{m \lambda}{d} ]

Where m which is the order of the interference is 1

substituting values

       \theta  =  sin ^{-1}[\frac{1 *721*10^{-9}}{ 77.7*10^{-6}} ]

      \theta  = 0.5317 ^o

 Now the width of first minimum  of the interference pattern is mathematically evaluated as

       Y  =  D sin \theta

substituting values

       Y  = 2.283 * sin (0.5317)

       Y  =  0.02 12 \ m

 Now the width of  the  pattern's central maximum is mathematically evaluated as

        Z =  2 * Y

substituting values

      Z = 2 * 0.0212

     Z = 0.0424 \ m

3 0
4 years ago
A certain tuning fork vibrates at a frequency of 215 Hz while each tip of its two prongs has an amplitude of 0.832 mm. (a) What
Marysya12 [62]

Explanation:

It is given that,

Frequency of vibration, f = 215 Hz

Amplitude, A = 0.832 mm

(a) Let T is the period of this motion. It is given by the following relation as :

T=\dfrac{1}{f}

T=\dfrac{1}{215}

T=4.65\times 10^{-3}\ s

(b) Speed of sound in air, v = 343 m/s

It can be given by :

v=f\times \lambda

\lambda=\dfrac{v}{f}

\lambda=\dfrac{343\ m/s}{215\ Hz}

\lambda=1.59\ m

Hence, this is the required solution.

5 0
4 years ago
If forces acting on an object are unbalanced, which factor may result from an unbalanced force
yan [13]

Answer:

Apply Newton's Second Law:

The acceleration of the object is proportional to the applied force.

4 0
3 years ago
Which statement is correct based on the data provided?
Ksivusya [100]

Answer:

I think D. Since a vacuum iswhere gravity is concentrated. not sure

3 0
3 years ago
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