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3 years ago

12

Radar use reflected microwaves to detect objects and measure their... what?

1 answer:

Sloan [31]3 years ago

7 0

Height and depth..... for sure....

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S.I. Units Ampere is use for what?

lawyer [7]

The ampere (symbol: A) is the SI base unit of electric current equal to one coulomb per second.

The ampere is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross section, and placed 1 meter apart in vacuum, would produce between these conductors a force equal to 2 times 10–7 newton per meter of length.

Electric current is the time rate of change or displacement of electric charge.

One ampere represents the rate of 1 coulomb of charge per second.

The ampere is defined first (it is a base unit, along with the meter, the second, and the kilogram), without reference to the quantity of charge.

The unit of charge, the coulomb, is defined to be the amount of charge displaced by a one ampere current in the time of one second.

This is your answer friend. Hope it helps you.

3 0

3 years ago

An airplane flies 1350km in 2 1/4 hours. What is its average speed in kilometers per hour?

Brut [27]

600km since it would be 1350 divided by 2.25

8 0

3 years ago

If a wave has a velocity of 100m/s and a wavelength of 10m, what is the frequency?

ratelena [41]

F=2 hz i think not sure

4 0

3 years ago

Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use

Mariana [72]

Answer:

The mass of the banana is m and it is at height h.

Applying the Law of Conservation of Energy

Total Energy before fall = Total Energy after fall

$E_{i}$ = $E_{f}$

Here, total energy is the sum of kinetic energy and potential energy

$K.E_{i}$ + $P.E_{i}$ = $K.E_{f}$ + $P.E_{f}$ (a)

When banana is at height h, it has

$K.E_{i}$ = 0 and $P.E_{i}$ = mgh

and when it reaches the river, it has

$K.E_{f}$ = 1/2m $v^{2}$ and $P.E_{f}$ = 0

Putting the values in equation (a)

0 + mgh = 1/2m $v^{2}$ + 0

mgh = 1/2m $v^{2}$

<em>cutting 'm' from both sides</em>

<em> </em>gh = 1/2 $v^{2}$

v = $\sqrt{2gh}$

Hence, the velocity of banana before hitting the water is

v = $\sqrt{2gh}$

6 0

3 years ago

A stone was dropped off a cliff and hit the ground with a speed of 104 ft/s. what is the height of the cliff? (use 32 ft/s2 for

katovenus [111]

Let the stone is dropped off a cliff of height S m ft.

Given, initial velocity of the stone, u= 0 ft/s

Final velocity of the stone, v= 104 ft/s

Acceleration of the stone= Acceleration due to gravity = 32 ft/s²

Using the third equation of motion,

v² - u² = 2aS

Substituting the values we get,

$(104)^{2}-(0)^{2}=2*32*S$

S= 169 ft

Height of the cliff is 169 ft.

5 0

3 years ago

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