Answer:
Part A the answer is the dielectric constant.
Part B Mica- mylar- paper- quartz
Explanation:
The capacity of a capacitor is given by
C = ε ε₀ A / d
Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.
Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor
the flexibility of the material must also be taken into account
Part A the answer is the dielectric constant.
Pate B order the materials from best to worst
Mica. The best ever
Mylar Flexible
Paper Low capacity, low working voltage, flexible
Quartz high dielectric, but brittle
solution:
1.6 m/s = 96 m/min (in other words, 1.6 m/s x 60 s/min)
96 m/min x 8.3 min = 796.8 m
You'd have an easier time using the equation if you understood where the equation comes from.
The law here ... the major principle to remember, the key, the fundamental truth, the big cookie ... is the fact that momentum is conserved. <em>The total momentum after they join up is the same as the total momentum before they meet.</em>
Momentum of an object is (mass) times (speed).
Now, list all the things you know, before and after the putty meets the ball:
<u>Before:</u><u> </u>There are two objects.
Mass of putty = 3 kg
Speed of putty = 5m/s
Momentum of putty = 3 x 5 = 15 kg-m/s.
Mass of ball = 5 kg
Speed of ball = zero
Momentum of ball = 5 x 0 = zero
Total momentum of both things = 15 kg-m/s
<u>After</u>: There is only one object, because they stuck together.
Mass of (putty+ball) = (3+5) = 8 kg
Speed of (putty+ball) = we don't know; that's what we have to find
Momentum of (putty+ball) = 8 x (speed)
===================================
We know that the momentum after is equal to the momentum before.
8 x (speed) = 15 kg-m/s
Divide each side by 8 :
Speed = 15 / 8 = <em>1.875 m/s </em> after they stick together.
Answer:
yes
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
