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slega [8]
3 years ago
9

Which of the following is a key component of the U.S. Space Shuttle program?

Physics
2 answers:
Sedaia [141]3 years ago
7 0
I would say the most key component is the us space shuttle
Angelina_Jolie [31]3 years ago
6 0
The thrid answeer is right
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mass and weight are similar, but not the same thing. In which of the following examples would the objects weight change, but mas
OverLord2011 [107]

When an astronaut travels from the earth to the moon, her weight changes, but her mass remains constant.  <em>(C ).</em>

7 0
3 years ago
A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net for
Dmitriy789 [7]

Answer:

The answer  is The acceleration is double its original value.

Explanation:

<h2><u>It is because of the second trial of accelaration. Because of this, an object's acceleration doubles from its original value.</u></h2><h2><u></u></h2>

Hope this helps....

Have a nice day!!!!

6 0
3 years ago
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Despite a very strong wind, a tennis player
Gnoma [55]

Answer:

Option 5. 1 and 3

Solution:

The only forces acting on the tennis ball after it has left contact with the racquet and the instant before it touches the ground are the force of gravity in the downward direction and the force by the air exerted on the ball.

The ball after it left follows the path of trajectory and as it moves forward in the horizontal direction the force of the air acts on it.

In the whole projectile motion of the ball, the acceleration due to gravity acts on the ball thus the force of gravity acts on the ball in the downward direction  before it hits the ground.

6 0
3 years ago
Calculate the force of attraction between
vagabundo [1.1K]

Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

G=6.673*10^-11Nm^2kg^2

We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

F=3.3365*10^-8/0.01

F=3.3365*10^-6

4 0
3 years ago
A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled
Damm [24]

Answer:

2.5

Explanation:

The capacitance of a parallel-plate capacitor filled with dielectric is given by

C=kC_0

where

k is the dielectric constant

C_0 is the capacitance of the capacitor without dielectric

In this problem,

C_0=1.2 nF is the capacitance of the capacitor in air

C=3.0 nF is the capacitance with the dielectric inserted

Solving the equation for k, we find

k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5

3 0
3 years ago
Read 2 more answers
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