We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:
PV=nRT
We manipulate this equation to give us an expression which will correspond to density. We do as follows:
PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L
If you have 9 moles of hydrogen gas(H2) the moles of water that can be formed is 9 moles
<u><em>calculation</em></u>
2H2 +O2→ 2H2O
The mole of H2O is calculated using the mole ratio.
that is H2:H2O is 2:2 into simple form = 1:1
therefore if 9 moles of H2 reacted the moles of H2O = 9 x1/1 = 9 moles
<span> (0.20948 x 31.998) / (
(0.78084 x 28.013) +
(0.20948 x 31.998) +
(0.00934 x 39.948) +
(0.000375 x 44.0099) +
(0.00001818 x 20.183) +
(0.00000524 x 4.003) +
(0.000002 x 16.043) +
(0.00000114 x 83.80) +
(0.0000005 x 2.0159) +
(0.0000005 x 44.0128) ) = 0.23140 = 23.140% O by mass </span>
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please reffer
A mole is a unit used to convert between the number of atoms and grams in an element. The information given on the periodic table is based on a mole or 6.02 *10^23 atoms of the element.