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Furkat [3]
3 years ago
6

A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC

and the pressure is constant? Remember that ALL TEMPERATURES MUST BE IN KELVIN! First: we add 273 convert Celsius to Kelvin so 25.0oC becomes 298 K We have constant pressure, two temperatures and one volume so we will solve for V2
Chemistry
1 answer:
inn [45]3 years ago
7 0

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

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How many formula units are there in 450 g of Na2S04?
Mashutka [201]

Formula units in 450 g of Na_{2} So_{4} is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$\frac{450 g}{142.04 g/mol} =  3.2 moles

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.

So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.

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3 years ago
What is the potential energy of the bowling ball as it sits on top of the building?
Tju [1.3M]

Answer:

Potential energy is energy due to an object's height above the ground.

Potential energy = mass x gravity x height

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5. given the ratio of reactants, what is the possibility of obtaining di- and polychlorinated product? explain.
Vladimir79 [104]

The ratio of reactants is chlorination of <u>2,3</u> dimethyl butane the possibility of obtaining do and the polychlorinated product is not seen.

When a mixture of methane and chlorine is exposed to ultraviolet light a substitution reaction occurs and the organic product is chloromethane. Because there are various hydrogen atoms that can be extracted in the first propagation step.

Abstraction of a hydrogen atom from the middle carbon of propane results in 2-chloropropane. In the presence of sunlight, methane reacts with chlorine to form chloromethane. The chlorination of methane is a free radical substitution reaction. Chlorine cannot turn into free radicals in the dark, so no reaction takes place. Therefore, the presence of sunlight is essential for the reaction to proceed.

Learn more about The reactants here:- brainly.com/question/6421464

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3 0
1 year ago
5. A 4.44 L container holds 0.481 mol of O2 at 22.6°C. What is the pressure of the tank?
mamaluj [8]

Answer:  The pressure of the tank will be 2.63 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 4.44 L

n = number of moles = 0.481

R = gas constant =0.0821Latm/Kmol

T =temperature =22.6^0C=(22.6+273)K=295.6K

P=\frac{nRT}{V}

P=\frac{0.481mol\times 0.0821Latm/K mol\times 295.6K}{4.44L}=2.63atm

The pressure of the tank will be 2.63 atm

8 0
3 years ago
Read 2 more answers
The vapor pressure of pure pentane and pure hexane are 425 torr and 151 torr respectively. equal moles of pentane and hexane are
nadezda [96]

The mole fraction of pentane in the vapor is 0.291

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Using the formula for vapour pressure,

vapour pressure = P^{}°_{hex} × X_{hex} + P^{}°_{pen} × X_{pen}

vapour pressure = 151 ×  (1-X_{pen}) + 425 × X_{pen}

240 = 151 - 151X_{pen} + 425X_{pen}

240 - 151 = -  151X_{pen} + 425 X_{pen}

89 = 274 X_{pen}

\frac{89}{274} = X_{pen}

0.291 = X_{pen}

Therefore,  the mole fraction of pentane in the vapor is 0.291

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3 0
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