Answer:
The answer to this is
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
Explanation:
To solve the question, let us list out the given variables and their values
Mass of first marble m1 = 27.3g
Velocity of the first marble v1 = 21.0 cm/s
Mass of second marble m2 = 11.7g
Velocity of the second marble v2 = 12.6 cm/s
After collision va1 = unknown and va2 = 23.7 cm/s
From Newton's second law of motion, force = rate of change of momentum produced
Hence m1v1 + m2v2 = m1va1 + m2va2 or
va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s
The velocity of the 27.3Kg marble after collision is = 16.24 cm/s
Not elementary school work
Answer:
The 
of a substrate will be "10 μM".
Explanation:
The given values are:
![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)
Reaction velocity, 
As we know,
⇒ ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
On subtracting "40" from both sides, we get
⇒ 
⇒ 
Hope this helps :) remember your conversions and just practice it's fairly easy:)
Acetic acid can be prepared from ethane by oxidizing it. Acetic acid is generally a carboxylic acid. These acids can be made by the oxidation of alcohols using potassium dichromate(VI) solution with sulfuric acid. Ethane is made into acetic acid in two steps. First it is formed into an aldehyde and then to acetic acid.
