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Murrr4er [49]
4 years ago
6

Triangle ABC is an obtuse triangle with the obtuse angle at vertex B. Angle A must be

Mathematics
2 answers:
wlad13 [49]4 years ago
6 0
We have to find the correct statement for angle A in a triangle ABC, which is an obtuse triangle. We know that angle B is obtuse ( greater than 90 degrees ). Therefore angles A and C must be less than 90 degrees. Angle A can not be congruent to angle B ( angle B > angle A ). It can be congruent to angle C but just in case that ABC is an isosceles obtuse triangle. Answer: Angle A must be A ) less than 90 degrees.
sdas [7]4 years ago
5 0

Answer:

The answer is A buddy ;)

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A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

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s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

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4 years ago
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