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Lunna [17]
2 years ago
8

Determine whether the graph is that of a function by using the vertical-line test. If it is, use the graph to find (a) its domai

n and range (b) the intercepts, if any (c) any symmetry with respect to the x-axis, y-axis, or the origin​

Chemistry
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Answer:

Following are the solution to this question:

Explanation:

If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise.  They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:

In point a:

\to Domain= [-\pi ,\pi ]\\\\\to Range = [-1,1]

In point b:

Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.  

\to y-intercept = 1\\\\\to x-intercept = \frac{\pi}{2} ,- \frac{\pi}{2} \\\\

In point C:

Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.

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hammer [34]

Answer:

(Q1) 9.42 kJ.

(Q2) 1.999 kJ

Explanation:

Heat: This is a form of Energy that brings about the sensation of warmth.

The S.I unit of Heat is Joules (J).

The heat of a body depend on the mass of the body, specific heat capacity, and temperature difference. as shown below

Q = cm(t₂-t₁) ........................ Equation 1

(Q1)

Q = cm(t₂-t₁)

Where Q = amount of heat absorbed, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature.

Given: m = 229.1 g = 0.2991 kg, t₁ = 25.0 °C, 32.50 °C

Constant: c = 4200 J/kg.°C

Substituting into equation 1

Q = 0.2991×4200(32.5-25)

Q = 1256.22(7.5)

Q = 9421.65 J

Q = 9.42 kJ.

Hence the heat absorbed = 9.42 kJ

(Q2)

Q = cm(t₂-t₁)

Where Q = amount of heat required, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature.

Given: m = 34 g = 0.034 kg, t₁ = 9 °C, t₂ = 23 °C

Constant: c = 4200 J/kg.°C

Q = 0.034×4200(23-9)

Q = 142.8(14)

Q = 1999.2 J

Q = 1.999 kJ.

Thus the Heat required = 1.999 kJ

4 0
3 years ago
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Answer:

density of a piece of metal = 7 gr/ml

Explanation:

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