You just need to multiply the total mass by the decimal value of the part that is tin. 133.8*0.103=13.8g (following the rules of significant figures).
Quantitative means to count how many of something. The correct answer is B, It has two eyes. Hope this helps
<u>Answers:</u>
a. 131.85 grams
b. 134.69 grams
To calculate the number of grams in the number of moles given for each compound, consider the formula:
<em>Moles = No. of grams / molar mass</em>
Therefore, to find the gram it will become:
<em>No. of grams = moles x molar mass</em>
a. 0.410 mol of NaCl (sodium chloride)
Molar mass of NaCl = (286.14 + 35.45) = 321.59
No. of grams = moles x molar mass
No. of grams = 0.410 x 321.59 = 131.85 grams
b. 4.80 mol of C2H4 (ethylene)
Molar mass of C2H4 = (12.01 x 2) + (1.01 x 4) = 28.06
No. of grams = moles x molar mass
No. of grams = 4.80 x 28.06 = 134.69 grams
C. 2Fe2O3 would be the correct answer!
Our reaction balanced equation at equilibrium N2(g) + 3 H2(g) ↔ 2 NH3(g)
and we have the Kp value at equilibrium = 4.51 X 10^-5
A) 98 atm NH3, 45 atm N2, 55 atm H2
when Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
= 98^2 / (45 * 55^3) = 1.28 x 10^-3
by comparing the Kp by the Kp at equilibrium(the given value) So,
Kp > Kp equ So the mixture is not equilibrium,
it will shift leftward (to decrease its value) towards the reactants to achieve equilibrium.
B) 57 atm NH3, 143 atm N2, no H2
∴ Kp = [P(NH3)]^2 / [P(N2)]
= 57^2 / 143 = 22.7
∴Kp> Kp equ (the given value)
∴it will shift leftward (to decrease its value) towards reactants to achieve equilibrium.
c) 13 atm NH3, 27 atm N2, 82 atm H2
∴Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
= 13^2 / (27* 82^3) = 1.14 X 10^-5
∴ Kp< Kp equ (the given value)
∴it will shift rightward (to increase its value) towards porducts to achieve equilibrium.