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Eva8 [605]
3 years ago
12

Which chemical symbols will complete the equation for this single displacement reaction?

Chemistry
2 answers:
Gelneren [198K]3 years ago
3 0

2NaCl + Br2

This is because Na (Sodium) still needs to retain the coefficient or amount of two. Since Chlorine already has 2 on the reactants side, having a two in front would make sense so both elements can have a two.

Bromine would have the subscript of two as in the reactants side of the equation, it is also under the coefficient of two. Thus, it would need to carry it to the products side in order to keep the equation balanced.

Hope this helps!

Sveta_85 [38]3 years ago
3 0

<u>Answer:</u> The chemical equation for the given reaction is given below.

<u>Explanation:</u>

A single displacement reaction is defined as the reaction in which more reactive element displaces the less reactive element from its chemical reaction.

A+BX\rightarrow AX+B

Element A is more reactive than element B.

The chemical equation for the reaction of sodium bromide with chlorine gas follows:

2NaBr+Cl_2\rightarrow 2NaCl+Br_2

By Stoichiometry of the reaction:

2 moles of sodium bromide reacts with 1 mole of chlorine to produce 2 moles of sodium chloride and 1 mole of bromine gas.

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What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L
Nonamiya [84]

Answer:

The pressure is 1, 22 atm.

Explanation:

We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).

0°C=273 K   25°C= 273 + 25= 298 K

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3 0
3 years ago
What mass of carbon dioxide is formed when 1.75 mol of ethane burns completely in oxygen?
dybincka [34]

Answer:

There is a mass of 154 Grams of Carbon Dioxide.

Explanation:

One mole is equal to 6.02 × 10^23 particles.

This means we have 1.05 X 10^24 total particles of Ethane.

Each ethane particle contains 2 carbon atoms.

If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)

Carbon Dioxide has a molar mass of 44.01 g/mol

So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.

Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.

What you should end up with is 154 Grams of Carbon Dioxide.

Hope this helps (And more importantly I hope I didn't make any errors in my math lol)

As a side note this is all assuming that this takes place at STP conditions.

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