D is the answer to this question
Answer:
0,051g of O₂ are consumed
Explanation:
The reaction of precipitation of Fe(II) is:
4Fe(OH)⁺(aq) + 4OH⁻(aq) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s)
The moles of Fe(II) you have in 85ml of 0.075 M Fe(II) are:
0,085L×0,075M = 6,4x10⁻³ moles of Fe(II)
For the reaction, you require 4 moles of Fe(II) and 1 mol of O₂(g) to precipitate the iron. Thus, moles of O₂(g) you require are:
6,4x10⁻³ moles of Fe(II)× = 1,6x10⁻³ moles of O₂(g)
These moles are:
1,6x10⁻³ moles of O₂(g)× = <em>0,051g of O₂ are consumed</em>
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I hope it helps!
<span>Yes, that would be called an ionic~ bond.</span>
Answer:
Because for dilute and aqueous solutions the mass of solvent will be a very close value to the volume of solution.
Explanation:
Molar concentration is defined as:
And molal concentration is defined as:
And:
Msolution=Msolute+Msolvent
For <em>dilute solutions</em>, we have small amounts of solute, then we have:
Msolution=Msolute+Msolvent, and as the mass of solute is very small: Msolution≅Msolvent
If the solution is <em>also aqueous</em> (water as solvent), and considering that the density of water is around 1 gm/cm3 or 1 kg/m3:
Msolvent≅Msolution≅Vsolution
Therefore, if we look to the molar and molal equations, we have the same numerator in both (moles of solute) and nearby numbers for the denominator, giving to the molar and molal concentration close values.
Answer:
1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).
2. The difference in pH values is 4.95.
Explanation:
1. The pH of a compound can be found using the following equation:
First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.
<u>Trimethyl ammonium</u>:
We can calculate [H₃O⁺] using the Ka as follows:
(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺
1.0 - x x x
By solving the above equation for x we have:
x = 0.097 = [H₃O⁺]
<u>Phenol</u>:
C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺
1.0 - x x x
Solving the above equation for x we have:
x = 9.96x10⁻⁶ = [H₃O⁺]
Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.
2. The difference in pH values for the two acids is:
Therefore, the difference in pH values is 4.95.
I hope it helps you!