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melomori [17]
3 years ago
12

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpen

dicular to one end of the string. The string rotates at an angular speed of 38 rev/s, and its tip has a tangential speed of 69 m/s. What is the length of the rotating string?
Physics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

0.28899 m

Explanation:

v = Velocity = 69 m/s

\omega = Angular velocity = 39\times 2\pi\ rad/s

r = Radius of the motion

In rotational motion velocity is given by

v=r\omega

\\\Rightarrow r=\dfrac{v}{\omega}

\\\Rightarrow r=\dfrac{69}{38\times 2\pi}

\\\Rightarrow r=0.28899\ m

The length of the rotation string is 0.28899 m

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Six friends are at a pizzeria. They want to order enough pizza so that each person can eat at least 2/5 . ​ start fraction, 2, d
Lyrx [107]

Friend #1 gets at least 2/5 of a pizza.

Friend #2 gets at least 2/5 .

Friend #3 gets at least 2/5 .

Friend #4 gets at least 2/5 .

Friend #5 gets at least 2/5 .

Friend #6 gets at least 2/5 .

Sum . . . . . . . . . at least  12/5 of a pizza.

Simplify . . . . . . at least  2.4 pizzas.

-- If pizzas can be bought by the half, they should order at least <em>2-1/2 pizzas.</em>

-- If only whole pizzas have to be ordered, then they should order at least <em>3 pizzas.</em>

4 0
4 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
What is the ratio of a 0.7 in circle in centimeters.
kifflom [539]
I believe it would be 4.4
4 0
3 years ago
I am starting out as a pilot. What single engine make of airplane should I get (Cheaper to bye one and train than to rent it)?
hichkok12 [17]
You have to make sure you know what your doing plus if you have your license and stuff to fly you have to practice on a 25 minute course
7 0
3 years ago
Read 2 more answers
Additional Problem: A simple pendulum, consisting of a string (of negligible mass) of length L with a small mass m at the end, i
kykrilka [37]

Answer:

a)   v = √ 2gL  abd  b)  θ = 45º

Explanation:

a) for this part we use the law of conservation of energy,

Highest starting point

       Em₀ = U = mg h

Final point. Lower

       Em₂ = ½ m v²

      Em₀ = Em₂

      m g h = ½ m v²

      v = √2g h

      v = √ 2gL

b) the definition of power is the relationship between work and time, but work is the product of force by displacement

     P = W / t = F. d ​​/ t = F. v

If we use Newton's second law, with one axis of the tangential reference system to the trajectory and the other perpendicular, in the direction of the rope, the only force we have to break down is the weight

     sin θ = Wt / W

     Wt = W sin θ

This force is parallel to the movement and also to the speed, whereby the scalar product is reduced to the ordinary product

     P = F v

The equation that describes the pendulum's motion is

    θ = θ₀ cos (wt)

Let's replace

    P = (W sin θ) θ₀ cos (wt)

    P = W θ₀ sint θ cos (wt)

We use the equation of rotational kinematics

    θ = wt

    P = Wθ₀ sin θ cos θ

Let's use

   sin 2θ = 2 sin θ cos θ

   P = Wθ₀/2 sin 2θ

This expression is maximum when the sine has a value of one (sin 2θ = 1), which occurs for 90º,

    2θ = 90

    θ = 45º

5 0
3 years ago
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