In the vertical direction, the block is in equilibrium:
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
where <em>n</em> is the magnitude of the normal force exerted by the surface on the block, and <em>mg</em> is the block's weight. It follows that <em>n</em> = <em>mg</em> = 24.5 N.
In the horizontal direction, the applied force of 14 N is opposed on by the 3.5 N force due to friction, so that the net force gives the block an acceleration <em>a</em> such that
∑ <em>F</em> (horizontal) = 14 N - 3.5 N = <em>ma</em>
(a) The magnitude of friction <em>f</em> is proportional to the magnitude of the normal force such that <em>f</em> = <em>µn</em>, where <em>µ</em> is the coefficient of kinetic friction. So we have
3.5 N = <em>µ</em> (24.5 N) ==> <em>µ</em> ≈ 0.14
(b) The net force on the block is 14 N - 3.5 N = 10.5 N pointing in the direction of the block's motion.
(c) Solve for <em>a</em> above:
10.5 N = (2.5 kg) <em>a</em> ==> <em>a</em> = 4.2 m/s²
Answer:d= 0.0219m
Explanation:
P= force /area
Area =πr^2=πd^2/4
πd^2/4=force/pressure
πd^2/4=34/90000
πd^2/4=0.0003778
πd^2= 0.0003778*4
πd^2=0.001511
Since π=3.142
d^2= 0.001511/3.142
d^2= 0.000480
d= square root of 0.000480
d= 0.0219m
Make into improper fractions. Then make the denominators the same by finding the denominations' lowest common factor.
Answer:
d) precipitation
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