Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F =
q =
we calculate
q =
q =
Ra 7 10-12
q = 2.65 10⁻⁶ C
Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is
![v_x = 15 m/s](https://tex.z-dn.net/?f=v_x%20%3D%2015%20m%2Fs)
and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:
![d= v_x t =(15 m/s)(5 s)=75 m](https://tex.z-dn.net/?f=d%3D%20v_x%20t%20%3D%2815%20m%2Fs%29%285%20s%29%3D75%20m)
![](https://tex.z-dn.net/?f=%3Cb%3E%3Ci%3E)
Hi Pupil Here's Your answer :::
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An object moving with constant speed can be accelerated if direction of motion changes. For example, an object moving with a constant speed in a circular path has an acceleration because its direction of motion changes continuously.
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Hope this Helps . . . . . . . . .
The category of galaxy which does not have a distinctive shape is D. an irregular galaxy.
A spiral galaxy has a spiral shape, an elliptical galaxy has an elliptical shape, and a barred-spiral galaxy has a barred-spiral shape. The only galaxy type which does not have a constant shape is an irregular galaxy.
Answer:
, it flows through your community's sanitary sewer system to a wastewater treatment facility.