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svetoff [14.1K]
3 years ago
9

Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface _____________ is less than

ideal.
Physics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

Traction

Explanation:

Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface Traction is less than ideal.

Traction is an act of drawing or pulling something over a surface specially a road or a track or it also defined as the grip of a tire on road or a wheel on rail. So speed when entering a curve should be slower when the tire has low traction to avoid accident.

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A Micro –Hydro turbine generator is accelerating uniformly from an angular velocity of 610 rpm to its operating angular velocity
Salsk061 [2.6K]

Answer:

Angular displacement of the turbine is 234.62 radian

Explanation:

initial angular speed of the turbine is

\omega_i = 2\pi f_1

\omega_1 = 2\pi(\frac{610}{60})

\omega_1 = 63.88 rad/s

similarly final angular speed is given as

\omega_f = 2\pi f_2

\omega_2 = 2\pi(\frac{837}{60})

\omega_2 = 87.65 rad/s

angular acceleration of the turbine is given as

\alpha = 5.9 rad/s^2

now we have to find the angular displacement is given as

\theta = \omega t + \frac{1}{2}\alpha t^2

\theta = (63.88)(3.2) + (\frac{1}{2})(5.9)(3.2^2)

\theta = 234.62 radian

3 0
3 years ago
Are oil and water optically different
katovenus [111]

Answer:

Yes

Explanation:

Trust me

6 0
3 years ago
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A projectile is launched with an initial velocity of 25 m/s at an angle of 30° above the horizontal. The projectile reaches maxi
Alchen [17]

Answer:

x ≈ 56 m

Explanation:

vertical initial velocity =v_{0y}(t) = 25 m/s* sin(30°)= 12.5 m/s

height = h

h =v_{0y}t+\frac{at^{2}}{2} \\\\65m = 12.5m/s*t + \frac{9.8m/s^{2}*t^{2}}{2} \\\\t=2.584 s

t- time is found solving quadratic equation.

horizontal velocity = v_{0x}=25m/s*cos(30^{o})=21.65 m/s

Horizontal velocity is constant, so distance x=v_{0x}*t =21.65 m/s *2.584 s=55.9 = 56 m

6 0
3 years ago
8. A car travels at a constant velocity of 70 mph for one hour. By the end of the second hour, the car’s velocity was 60 mph. At
Mrac [35]

<u>Answer:</u>

  Positive acceleration is in third hour and negative acceleration is in second hour.

<u>Explanation:</u>

  Velocity of car in first hour =  70 mph

  Velocity of car in second hour = 60 mph

  Velocity of car in third hour = 80 mph

   Acceleration = Change in velocity / Time

   Acceleration in second hour = (60 - 70)/1 = -10 mph²

   Acceleration in third hour = (80 - 60)/1 = 20 mph²

   So positive acceleration is in third hour and negative acceleration is in second hour.

8 0
3 years ago
HELP ME PLEASE ASAP!!!!! WILL GIVE BRAINLIEST, FIVE STARS, AND HEART!!!!!<br>(picture included)
harina [27]

Answer:

Kinetic - a box moving

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