Answer:
94.67 N
Explanation:
Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.
At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.
Substituting 70 N for W, 41 N for F and 
for 37 degrees
N=70+41sin37=94.67441595 N and rounding off to 2 decimal places
N=94.67 N
The force of an object is tangential to a circle.... Hope it helps
Answer:
option A
Explanation:
given,
lamp position from pool wall = 2.5 m
height of the pool = 2.5 m
now,
from the triangle
θ = i = 45°
using Snell's law
n₁ sin i = n₂ sin r
n₁ =4/3 n₂ = 1
now,
r = sin⁻¹(0.9428)
r = 70.5°
hence, the correct answer is option A
The correct answer to this question is this one: B. 5.89 feet
<span>The area of a circular trampoline is 108.94 square feet. The radius of the trampoline is 5.89 feet.
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For a circle,
A = (pi)r^2
108.94 ft^2 = (pi)r^2
r^2 = (108.94 ft^2)/(pi)
r = sqrt(108.94/pi) ft
r = 5. 89 ft
Answer:
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
The purpose here is derive x(t) twice as follows:
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
