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2 years ago

Calculate the force applied (in newtons) if a pressure of 2000Pa is acting on an area of 3m2.

Physics

1 answer:

Bas_tet [7]2 years ago

5 0

P=F/A

Force= P * A = (2000 x 3) N = 6000N

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Assignments

sladkih [1.3K]

Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

$w=-F_f(d)$

$w=-(35)(20)$

$w=-700J$

B) What is the work done on the cart by the gravitational force?

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

$w=Fdcos90$

$w=0$

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

$W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J$

D) Find the force the shopper exerts, using energy considerations.

$F_f+Fcos25=0\\-35+Fcos25=0\\F=38.6N$

E) What is the total work done?

You just need to add them:

$w=wshopper+wfriction\\w=0$

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3 years ago

A charge of 12 passes through the filament of a car head lamp bulb in 4 s. what is current?

Katena32 [7]

Answer:

3 A

Explanation:

$current = \frac{charge}{time} \\ = \frac{12}{4} \\ = 3 \: amperes$

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3 years ago

I have no idea of how to approach this problem

nataly862011 [7]

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

$(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1$

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

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3 years ago