Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
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Answer:
v = 5.7554 m/s
Explanation:
First of all we need to know if the angle of the vine is measured in the horizontal or vertical.
To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:
h₀ = h sinα
h₀ = 5.32 sin43° = 3.6282 m
As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:
Δh = 5.32 - 3.63 = 1.69 m
In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:
Ep = Ek
From here, we can calculate the speed of the monkey.
Ep = mgΔH
Ek = 1/2 mv²
The potential energy is:
Ep = 16.9 * 9.8 * 1.69 = 279.9
Now with the kinetic energy:
1/2 * (16.9) * v² = 279.9
v² = (279.9) * 2 / 16.9
v² = 33.12
v = √33.12
<h2>
v = 5.7554 m/s</h2>
Hope this helps
Answer:
600 mC
Explanation:
The charge of an electron is 1.6 x 10-19C so for a current with 10 mA, the charge going to screen in one second is 10 mC
so number of electrons, n = (10 x 10-3)/(1.6 x 10-19) = 6.25 x 1016 so in a minute the charge is 10 * 60 = 600 mC
<span>With a half-life of 700 million years, U-235 would have had twice as much mass at a time 700 MYA. This would have put the mass at 100kg at that time. Going back another 50 million years would be (50/700) or 1/14 of the half-life, or (1/2 * 1/14), or 1/28 of the total mass. 1/28 of 100kg is 3.57kg, so the amount present at the 750MYA mark would be approximately 103.57kg of U-235.</span>
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