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Rom4ik [11]
4 years ago
9

Which explanation is based on scientific evidence?​

Physics
1 answer:
Yuki888 [10]4 years ago
5 0

Answer:

Scientific evidence is evidence that serves to either support or counter a scientific theory or hypothesis. Such evidence is expected to be empirical evidence and interpretable in accordance with scientific method.

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Two 3 m long conductors are separated from each other by 5 mm and carry a current of 10 A dc. Calculate the force that one condu
makkiz [27]

Answer:

0.012 N

Explanation:

The formula to apply is that adopted from the Ampere law which is;

F= μ* I₁*I₂*l /2πd   where

F is force that one conductor exerts on the other.

μ = magnetic permeability of free space = 4π×10⁻⁷ T. m/A

I₁ = current in conductor one=10 A

I₂ = current in conductor two= 10 A

l= length of conductor= 3 m

d= distance between the conductors = 5 mm = 0.005 m

Applying the values in the equation

F= 4π×10⁻⁷ *10*10*3 / 2π*0.005

F= 6 * 10⁻⁵ / 0.005

F=0.012 N

7 0
3 years ago
An electron in a hydrogen atom undergoes a transition from the n = 3 level to the n = 6 level. To accomplish this, energy, in th
Harlamova29_29 [7]

Answer:1.816\times 10^{-19} J

Explanation:

Given

E=\frac{hc}{\lambda }

E=2.18\times 10^{-18}(\frac{1}{n_1^2}-\frac{1}{n_2^2})

where h=Planck constant

c=speed of light

E=2.18\times 10^{-18}(\frac{1}{3^2}-\frac{1}{6^2})

E=2.18\times 10^{-18}\times \frac{1}{12}

E=1.816\times 10^{-19} J

7 0
3 years ago
1.) 450 cm =____m<br><br> 2.) 24 miles =____cm<br><br> 3.) 16.7 gallons =____liters
S_A_V [24]

Answer:

450cm = 4.5m

24miles = 3862430 cm (3.9×10⁶cm)

16.7 gallons = 63.216 liters (approx.)

Explanation:

brainliest plz

7 0
3 years ago
A 2000 kg car moves along a horizontal road at speed vo
cluponka [151]

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a (Eq. 1)

\Sigma F_{y} = N-m\cdot g = 0 (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

a = -\mu_{k}\cdot g (Eq. 3)

Where:

a - Deceleration of the car, measured in meters per square second.

\mu_{k} - Kinetic coefficient of friction, dimensionless.

g - Gravitational acceleration, measured in meters per square second.

If we know that \mu_{k} = 0.0735 and g = 9.807\,\frac{m}{s^{2}}, then deceleration of the car is:

a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )

a = -0.721\,\frac{m}{s^{2}}

The stopping distance of the car (\Delta s), measured in meters, is determined from the following kinematic expression:

\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a} (Eq. 4)

Where:

v_{o} - Initial speed of the car, measured in meters per second.

v - Final speed of the car, measured in meters per second.

If we know that v_{o} = 15.9\,\frac{m}{s}, v = 0\,\frac{m}{s} and a = -0.721\,\frac{m}{s^{2}}, stopping distance of the car is:

\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}

\Delta s = 175.319\,m

The shortest possible stopping distance of the car is 175.319 meters.

8 0
4 years ago
An Aichi D3A bomber, with mass of 3600 kg, departs from its aircraft carrier with a velocity of 85 m/s due east. What is the pla
Nataliya [291]

Answer:

306000 is the answer.......

7 0
3 years ago
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