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Alik [6]
3 years ago
10

to make a shade of lavender paint jon mixes 4 ounces of red tint and 28 ounces of blue tint into one gallon of white paint. if 2

0 gallons of white paint and 80 ounces of red tint are used, how much blue tint should be added?
Mathematics
2 answers:
sladkih [1.3K]3 years ago
5 0
4+20=24+28=52+80=132
(hope I helped)
Yakvenalex [24]3 years ago
3 0
For one gallon of white paint, 28 ounces of blue tint are used.  Since we use 20 gallons of white paint, multiply 28 by 20.
28 x 20 = 560
You need to use 560 ounces of blue tint for 20 gallons of white paint.
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A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta
Archy [21]

Answer:

\dfrac{11}{30}

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{3}{5}=0.6.

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is \dfrac{3}{10}=0.3.

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{1}{5}=0.2.

The probability to choose each urn is the same and is equal to \frac{1}{3}.

Thus, the probability that the marble is red is

\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.

4 0
3 years ago
A number r decreased by the quotient of a number r and two
worty [1.4K]
R - (12÷r)+2 
I think that thats the answer
4 0
3 years ago
Stella has points card for a movie theater
Basile [38]
Answer:
12.5v+25=130
v=8.4
You can’t visit 8.4 times. So you would need to visit 9 times to get a sufficient amount for a ticket.
4 0
2 years ago
Please explain, thank you
RoseWind [281]

Answer:

C. 2.

Step-by-step explanation:

The graph descends from the left  so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below.  The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.

f(x) = a(x + 20)(x - 6.5)(x - 13)   where a is  a negative constant.

(This is only an approximation).

By the Remainder theorem, when the expression is divided by (x + 10):

f(-10) = -20 so we have

-20 = a (-10 + 20)(-10-6.5)(-10 - 13)

(10)(-16.5)(-23)a = -20

a = -20 / (10)(-16.5)(-23)

a = -0.0053

When  the equation is divided by (x - 10) then f(10)  is the remainder so substituting we have as the remainder:

-0.0053(10+20)(10-6.5)(10 -13)

-0.0053 * 30 * 3.5 * -3

= 1.7 approximately.

Looks like the answer is 2.

3 0
3 years ago
g A population is infected with a certain infectious disease. It is known that 95% of the population has not contracted the dise
trasher [3.6K]

Answer:

There is approximately 17% chance of a person not having a disease if he or she has tested positive.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = a person has contracted the disease.

+ = a person tests positive

- = a person tests negative

The information provided is:

P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01

Compute the missing probabilities as follows:

P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99

The Bayes' theorem states that the conditional probability of an event, say <em>A</em> provided that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}

Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:

P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}

              =\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667

So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.

As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.

7 0
3 years ago
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