How many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 12 % alcohol solut

Question

3 years ago

14

ion?

1 answer:

Tom [10] · Answer 1 · 2022-06-07T03:53:42+03:00

Answer:

27oz

Explanation:

Let the volume quantity of the 10% solution = x

The volume quantity of the 15% alcohol solution is known as = 18oz

Therefore the volume of the 12% product = 18oz + x

Therefore

0.10 × x + 0.15 × 18oz = 0.12 × (18oz+x)

0.15×18oz - 0.12×18oz = 0.12×x - 0.10×x

.

0.03*18oz = 0.02x

Dividing both sides by 0.02

x = 27oz

Verifying the answer, we have

0.1 × 27 + 18 × 0.15 = 0.12 × 45

2.7 + 2.7 = 5.4

How many ounces of a 10 % alcohol solution must be mixed with 18 ounces of a 15 % alcohol solution to make a 12 % alcohol​ solut