Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm This is a Boyle’s law gas problem

1 answer:

3 0

P1/V1=P2/V2
1/22.4=4/x
X=4 multiple by 22.4
V2=89.6L

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