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djyliett [7]
3 years ago
14

If the archerfish spits its water 60 degrees from the horizontal aiming at an insect 1.4 m above

Physics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

6.1 m/s

Explanation:

Take up to be positive.  Given (in the y direction):

Δy = 1.4 m

vᵧ = 0 m/s

g = -10 m/s²

Find: v₀ᵧ

vᵧ² = v₀ᵧ² + 2aΔy

(0 m/s)² = v₀ᵧ² + 2 (-10 m/s²) (1.4 m)

v₀ᵧ = 5.29 m/s

The vertical component is 5.29 m/s.  So the total magnitude of the initial velocity is:

v₀ᵧ = v₀ sin θ

5.29 m/s = v₀ sin 60°

v₀ = 6.11 m/s

Rounding to two significant figures, the fish must spit the water at 6.1 m/s.

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A helium-filled balloon is launched when the temperature at ground level is 27.8°c and the barometer reads 752 mmhg. if the ball
ololo11 [35]
The helium may be treated as an ideal gas, so that
(p*V)/T =constant
where
p = pressure
V = volume
T = temperature.

Note that
7.5006 x 10⁻³ mm Hg = 1 Pa
1 L = 10⁻³ m³

Given:
At ground level,
p₁ = 752 mm Hg
     = (752 mm Hg)/(7.5006 x 10⁻³ mm Hg/Pa)
     = 1.0026 x 10⁵ Pa
V₁ = 9.47 x 10⁴ L = (9.47 x 10⁴ L)*(10⁻³ m³/L)
     = 94.7 m³
T₁ = 27.8 °C = 27.8 + 273 K
     = 300.8 K

At 36 km height,
P₂ = 73 mm Hg = 73/7.5006 x 10⁻³ Pa
     = 9.7326 x 10³ Pa
T₂ = 235 K

If the volume at  36 km height is V₂, then
V₂ = (T₂/p₂)*(p₁/T₁)*V₁
     = (235/9.7326 x 10³)*(1.0026 x 10⁵/300.8)*94.7
     = 762.15 m³

Answer: 762.2 m³  
3 0
3 years ago
A strip of copper 150 µm thick and 4.50 mm wide is placed in a uniform magnetic field of magnitude B = 0.74 T, that is perpendic
Sophie [7]

Answer:

V = 6.55*10^{-6} v

Explanation:

The number density can be determined by using below formula:

n = \frac{Bi}{Vle}

where,

B  is uniform magnetic field 0.74

i is current 18 A

V is hall potential difference

l is thickness 150 MICRO METER

e is electron charge 1.6 *10^{-19} C

therefore V can be determined as

V = \frac{iB}{nle}

V = \frac{18*0.74}{8.47*10^{28}*150*10^{-6}*1.6 *10^{-19}}

V = 6.55*10^{-6} v

8 0
3 years ago
In Ancient Greece, athletes competing in the long jump used handheld weights called halteres to lengthen their jumps. You are a
katovenus [111]

The halter add the distance to the jump in meters is 0.55 m.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

Maximum height gained when final velocity is zero

Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

ΔR = ΔVx' x t

ΔR = 1.34 x 0.41

ΔR =0.55m

Thus, the halter add the distance to the jump in meters is 0.55 m.

Learn more about projectile.

brainly.com/question/11422992

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3 0
2 years ago
How does the input distance of a single fixed pulley compare to the out- put distance?
ololo11 [35]

A pulley is another sort of basic machine in the lever family. We may have utilized a pulley to lift things, for example, a banner on a flagpole.

<u>Explanation:</u>

The point in a fixed pulley resembles the support of a lever. The remainder of the pulley behaves like the fixed arm of a first-class lever, since it rotates around a point. The distance from the fulcrum is the equivalent on the two sides of a fixed pulley. A fixed pulley has a mechanical advantage of one. Hence, a fixed pulley doesn't increase the force.

It essentially alters the direction of the force. A moveable pulley or a mix of pulleys can deliver a mechanical advantage of more than one. Moveable pulleys are appended to the item being moved. Fixed and moveable pulleys can be consolidated into a solitary unit to create a greater mechanical advantage.

4 0
3 years ago
A car accelerates from rest at 5.75m/s2 for 4.4 sec when it runs out of pavement and runs into some mud. In the mud it accelerat
just olya [345]

Answer:

113.85 m

Explanation:

When the car is on the pavement:

v₀ = 0 m/s

a = 5.75 m/s²

t = 4.4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4.4 s) + ½ (5.75 m/s²) (4.4 s)²

Δx = 55.66 m

v = at + v₀

v = (5.75 m/s²) (4.4 s) + 0 m/s

v = 25.3 m/s

When the car is in the mud:

v₀ = 25.3 m/s

v = 0 m/s

a = -5.5 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (25.3 m/s)² + 2 (-5.5 m/s²) Δx

Δx = 58.19 m

The total displacement is therefore:

55.66 m + 58.19 m = 113.85 m

4 0
4 years ago
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