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Effectus [21]
3 years ago
14

Unpolarized light is passed through an optical filter that is oriented in the vertical direction.

Physics
1 answer:
VashaNatasha [74]3 years ago
5 0

In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.

Malus's law warns that

I = I_0 cos^2\theta

Where,

\theta= Angle between the analyzer axis and the polarization axis

I_0 =Intensity of the light before passing through the polarizer

The intensity of the beam from the first polarizer is equal to the half of the initial intensity

I = \frac{I_0}{2}

Replacing with our the numerical values we get

I = \frac{46}{2}

I = 23W/m^2

Therefore the  intensity of the light that emerges from the filter is 23W/m^2

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kinetic energy = 0.5 x mass x x velocity^{2}

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from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

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