Answer:
(B) The total internal energy of the helium is 4888.6 Joules
(C) The total work done by the helium is 2959.25 Joules
(D) The final volume of the helium is 0.066 cubic meter
Explanation:
(B) ∆U = P(V2 - V1)
From ideal gas equation, PV = nRT
T1 = 21°C = 294K, V1 = 0.033m^3, n = 2moles, V2 = 2× 0.033=0.066m^3
P = nRT ÷ V = (2×8.314×294) ÷ 0.033 = 148140.4 Pascal
∆U = 148140.4(0.066 - 0.033) = 4888.6 Joules
(C) P2 = P1(V1÷V2)^1.4 =148140.4(0.033÷0.066)^1.4= 148140.4×0.379=56134.7 Pascal
Assuming a closed system
(C) Wc = (P1V1 - P2V2) ÷ 0.4 = (148140.4×0.033 - 56134.7×0.066) ÷ 0.4 = (4888.6 - 3704.9) ÷ 0.4 = 1183.7 ÷ 0.4 = 2959.25 Joules
(C) Final volume = 2×initial volume = 2×0.033= 0.066 cubic meter
According to Archimede's principle, a physical object experiences an upthrust due to a difference in pressure between upper and lower surfaces.
<h3>What is an
upthrust?</h3>
An upthrust is also referred to as buoyancy and it can be defined as an upward force which is exerted by a fluid (liquid or gas), so as to oppose the weight of a partially or fully immersed physical object that is floating in it.
Based on scientific information, a physical object experiences an upthrust when it is immersed in a fluid due to a difference in height and pressure between upper (top) and lower (bottom) surfaces.
According to Archimede's principle, there is a higher pressure at the bottom of the physical object due to height, and a lower pressure at the top of the physical object.
Read more on upthrust here: brainly.com/question/24389514
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<span>The lighter object is in orbit around the heaviest, and the Sun is the heaviest object in the Solar System</span>
Answer:
Energy = 780 Joules
Explanation:
Given the following data;
Power = 78 Watts
Time = 10 seconds
To find the energy transferred;
Energy refers to the amount or quantity of power which is being consumed by an individual, group of people or organization over a specific period of time.
Mathematically, energy is given by the formula;
Energy = power * time
Energy = 78 * 10
Energy = 780 Joules
Therefore, the amount of energy the turbine transferred is 780 Joules
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