3 years ago

The force that one surface exerts on another when the 2 rub against each other is called

Chemistry

2 answers:

Sav [38]3 years ago

5 0

The friction force
________________________________________________________

harkovskaia [24]3 years ago

3 0

friction

it should be friction... if not my bad

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The IUPAC name of the missing product for the following reactions will be. 2-butene + water →

alex41 [277]

Answer:

2-butanol or butan-2-ol

Explanation:

This is an example of hydrolysis of alkene to give alkanol

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3 years ago

Argon makes up 0.93% by volume of air. Calculate its solubility (in mol/L) in water at 20°C and 1.0 atm. The Henry's law constan

ivolga24 [154]

Answer : The solubility is, $1.4\times 10^{-5}mol/L$

Explanation : Given,

$k_H$ = Henry's law constant of argon = $1.5\times 10^{-3}mol/L.atm$

First we have to calculate the pressure of argon.

Pressure of argon = $1.0atm\times \frac{0.93}{100}$

Pressure of argon = 0.0093 atm

Now we have to calculate the solubility.

As, the solubility of argon in 1 atm pressure = $1.5\times 10^{-3}mol/L$

So, the solubility of argon in 0.0093 atm pressure = $\frac{0.0093atm}{1atm}\times 1.5\times 10^{-3}mol/L$

= $1.4\times 10^{-5}mol/L$

Thus, the solubility is, $1.4\times 10^{-5}mol/L$

7 0

3 years ago

A student collects 25 mL of gas at 0.98 bar. What volume would this gas occupy at 1.013 bar? * 3 points 25.8 mL 24.2 mL .09 mL 3

trasher [3.6K]

Answer:

24.2 mL.

Explanation:

Assuming constant temperature, we can solve this problem using Boyle's law, which states:

P₁V₁=P₂V₂

Where:

P₁ = 0.98 bar

V₁ = 25 mL

P₂ = 1.013 bar

V₂ = ?

We input the data:

0.98 bar * 25 mL = 1.013 bar * V₂

And solve for V₂:

V₂ = 24.18 mL

The closest option is the second one: 24.2 mL.

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3 years ago

What are the natural components of water?

DerKrebs [107]

two hydrogen atoms and one oxygen atom. hope this helped.

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3 years ago

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What would be the effect on this reaction of increasing the temperature?

RideAnS [48]

the correct answer to this question is C

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