The reaction of N2 and H2 to generate NH3 is as follows:N2 + 3H2 ⇒2NH3
Since H2 is in excess amount in this reaction, the determine factor is N2. The ratio of N2 and product NH3 is 1:2. Therefore, 4.08 moles of N2 can generate 4.08*2 = 8.16 mole of NH3.
Grams of NH3 = moles of NH3 * molar mass of NH3 = 8.16 mole * 17 g/mole = 139 g.
139 grams of nh3 can be produced from 4.08 mol of n2 and excess h2.
Answer:
4:16
Quick Facts
Species
Native
Size
5 to 6 inches in length
Habitat
Muddy marshes, tidal creeks and grass flats and along sheltered shores. In summer, may range along a hundred feet of the shoreline and a few yards offshore. During colder months, often retreat to deeper waters or burrow six to eight inches deep in bottom mud or silt.
Range
Abundant, permanent residents of the entire Chesapeake Bay. Found on the Atlantic coast of North America from Labrador, Canada, to Mexico.
Diet
Diet includes algae, plants, insects, small crustaceans and mollusks, other fish and carrion
Lifespan Up to 3 years
Answer:
60
Explanation:
The formula of the compound is given as:
HC₂H₃O₂
To find the formula mass we sum up the atomic masses of the component elements;
Atomic mass:
H = 1
C = 12
O = 16
HC₂H₃O₂ = 1 + 2(12) + 3(1) + 2(16)
= 1 + 24 + 3 + 32
= 60
The difference between ordinary, analar and industrial reagents is the in the purity. Ordinary reagents are those whose purity meets the standard. Analar reagents are used in chemical analysis and they are of high purity but with known contaminants which again illustrates their use in chemical analyses.Finally the industrial reagents are not pure enough and they are used for industrial purposes as well for commercial use.