Answer:
i. Molar mass of glucose = 180 g/mol
ii. Amount of glucose = 0.5 mole
Explanation:
<em>The volume of the glucose solution to be prepared</em> = 500 
<em>Molarity of the glucose solution to be prepared</em> = 1 M
i. Molar mass of glucose (
) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol
ii.<em> mole = molarity x volume</em>. Hence;
amount (in moles) of the glucose solution to be prepared
= 1 x 500/1000 = 0.5 mole
Answer:
Electronic configuration of nitrogen: K=2 L=5
Electronic configuration of phosphorus : K = 2 L = 8 M = 5
The element nitrogen will be more electronegative because of the smaller size of its atom. nitrogen accepts electrons more easily.
Explanation:
Answer:
d
Explanation:
HF gives its H to HPO42 making it H2PO4, so HF is the acid and F- is the conj base
Answer:
a) equivalence point
b) direct titration
c) primary standard
d) titrand
e) Back titration
f) back titration
g) standard solution
h) standard solution
I) indirect titration
j) end point
Explanation:
A volumetric analysis is one in which a solution of unknown concentration is determined from its volume. This is commonly referred to as titration.
In titration, a standard solution is reacted with another solution of unknown concentration. The point at which the concentration of the standard solution is equal to that of the analyte is known as the equivalence point (usually indicated by a colour change). An indicator may be added to the analyte solution to help identify when the reaction is complete.
